Consider the rotating disk of Problem 6.16. A disk-shaped, stationary plate is placed a short distance away from the rotating disk, forming a gap of width g. The stationary plate and ambient air are at
where
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- I need right solution with clear calculations.arrow_forwardProblem 1. For uniform flow over a flat plate, a useful approximation for the x-component of velocity in an incompressible laminar boundary layer is a parabolic variation from the velocity at the surface, u (y = 0) = 0 due to no-slip condition, to the free-stream velocity at the edge of the boundary layer, u (y = 8) = U. The equation for the profile is given by u/U = 2 (y/d) – (y/8)², where d = cx 1/2 and c is a constant - (a) Show that the simplest expression for the y-component of velocity is (b) Plot u/U and v/U versus y/d at x = separate graphs. 2 *=4[4(9)²¯ +(9)*] = 0.50 m where = 5.0 mm. Use the x-axis for velocity and plot on (c) Find the maximum value for v/U at this location and discuss its magnitude compared to u/U. АУ u(x, y) Uarrow_forwardUsing the theory on boundary layer and flow separation, explain how the pressure drop across a sudden contraction is not equal to the change in velocity of the fluid. Relate this to how conical reducers are more preferred than a flanged contraction shown in the figure below. Direction of flow C-C Plone of vena contractoarrow_forward
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- A cylindrical tank of radius rrim = 0.354 m rotates about its vertical axis. The tank is partially filled with oil. The speed of the rim is 3.61 m/s in the counterclockwise direction (looking from the top), and the tank has been spinning long enough to be in solid-body rotation. For any fluid particle in the tank, calculate the magnitude of the component of vorticity in the vertical z-directionarrow_forwardKNOWN: Speed and temperature of atmospheric air flowing over a flat plate of prescribed length and temperature. FIND: Rate of heat transfer corresponding to Rex,c = 10°, 5 × 10³ and 106. SCHEMATIC: Air U∞=25m/s Too=25°C p=1atm 个个个 19 -TS=125°C ASSUMPTIONS: (1) Flow over top and bottom surfaces. L=1m PROPERTIES: Table 4-4, Air (T+= 348K, 1 atm): p = 1.00 kg/m³, v = 20.72 x 10 = 0.0299 W/m-K, Pr = 0.700. m /s, karrow_forwardyes it is hard questoin that is why I am looking for helparrow_forward
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