Chapter 2.5, Problem 53AYU

In Problems 39-62, graph each function using the techniques of shifting, compressing, stretching, and/or reflecting. Stan with the graph of the basic function (for example, $y\text{ = }{x}^2$) and show all stages. Be sure to show at least three key points. Find the domain and the range of each function.

53. $g\left(x\right)\text{ = 2}\sqrt{x\text{ - 2}}\text{ + 1}$

To determine

To graph: The function $f\left(x\right)=2\sqrt{x -2}+1$, using the techniques of shifting, compressing, stretching, and/or reflecting. Start with the graph of the basic function (for example, $y=x^2$) and show all stages. Be sure to show at least three key points. Find the domain and the range of each function.

Answer to Problem 53AYU

Domain of the function $f\left(x\right)=2\sqrt{x -2}+1$ is $\left[2,\infty \right)$.

Range of the function $f\left(x\right)=2\sqrt{x -2}+1$ is $\left[1,\infty \right)$.

Explanation of Solution

Given:

$f\left(x\right)=2\sqrt{x -2}+1$

Graph:

Now use the following steps to obtain the graph of $f\left(x\right)$.

Step 1: The function $f\left(x\right)=\sqrt{x}$ is the square root function.

$f\left(x\right)=\sqrt{x}$     square root function

Step 2: To obtain the graph of $f\left(x\right)=\sqrt{x-2}$, replace $x$ by $x-2$ from each $y\text{-coordinate}$ on the graph of $f\left(x\right)=\sqrt{x}$, that it is shifted right 2 units.

$f\left(x\right)=\sqrt{x-2}$     replace $x$ by $x-2$; Horizontal shift right 2 units.

Step 3: To obtain the graph of $f\left(x\right)=2\sqrt{x -2}$, multiply each $y\text{-coordinate}$ of the graph of $f\left(x\right)=\sqrt{x-2}$, by 2, that it is vertically stretched by the factor of 2.

$f\left(x\right)=2\sqrt{x -2}$     Multiply by 2, vertically stretched by a factor of 2

Step 4: To obtain the graph of $f\left(x\right)=2\sqrt{x -2}+1$, add 1 from each $y\text{-coordinate}$ on the graph of $f\left(x\right)=2\sqrt{x -2}$, that it is shifted up 1 unit.

$f\left(x\right)=2\sqrt{x -2}+1$     add 1, vertically shift up 1 unit.

Interpretation:

Domain of the function $f\left(x\right)=2\sqrt{x -2}+1$ is $\left[2,\infty \right)$.

Range of the function $f\left(x\right)=2\sqrt{x -2}+1$ is $\left[1,\infty \right)$.