Chapter 2, Problem 13CR

In problems 11-14, graph each equation.

$x^2+{\left(y-3\right)}^2=16$

To determine

To plot: The graph of the given equation $x^2+{\left(y-3\right)}^2=16$.

Answer to Problem 13CR

Solution:

Explanation of Solution

Given:

$x^2+{\left(y-3\right)}^2=16$

Graph:

The given equation is $x^2+{\left(y-3\right)}^2=16$.

The graph of the given equation is plotted as shown below:

From the graph, we find that the center of the circle is located at $\left(0,3\right)$ with a radius of 4 units.