Chapter 14.2, Problem 10PP

Interpretation Introduction

Interpretation:

Mass of sodium hypochlorite $\left(NaOCl\right)$ is to be calculated where the percent by mass of sodium hypochlorite $\left(NaOCl\right)$ in bleach solution is $3.62\%.$

Concept introduction:

The concentrations of solutions are expressed in different ways, all of them involved in the quantity of solute and the quantity of solution or solvent. Among them, Mass percentage (w/W percent) is used to express the concentration of solution.

Mass percentage (w/W percent):

Percent by mass usually describes solutions in which solute is solid and solvent is liquid. It is expressed as the ratio of the mass of the solute to the mass of the solution multiplied by 100. (The mass of the solution = mass of the solute + mass of the solvent)

In expression, $\mathrm{Mass}percentage\left(w/W\right)\%= \frac{Massofsolute}{Massofsolution}\times 100$

Answer to Problem 10PP

Mass of sodium hypochlorite $\left(NaOCl\right)$ is $54.3g$.

Explanation:

In expression, $\mathrm{Mass}percentage\left(w/W\right)\%= \frac{Massofsolute}{Massofsolution}\times 100$

If we write in equation,

$\mathrm{Percent}bymassofNaOClinbleachsolution=\frac{MassofNaOCl}{Massofbleachsolution} \times 100$

Data given: Percent by mass of $\left(NaOCl\right)$ in bleach solution = $3.62\%.$

Mass of the bleach solution = $1500gm$

$3.62\%=\frac{MassofNaOCl}{1500} \times 100$

So, Mass of $\left(NaOCl\right)$ $=\frac{1500\times 3.62}{100} g$

= $54.3g$

Mass of sodium hypochlorite $\left(NaOCl\right)$ is $54.3g$.

Explanation of Solution

In expression, $\mathrm{Mass}percentage\left(w/W\right)\%= \frac{Massofsolute}{Massofsolution}\times 100$

If we write in equation,

$\mathrm{Percent}bymassofNaOClinbleachsolution=\frac{MassofNaOCl}{Massofbleachsolution} \times 100$

Data given: Percent by mass of $\left(NaOCl\right)$ in bleach solution = $3.62\%.$

Mass of the bleach solution = $1500gm$

$3.62\%=\frac{MassofNaOCl}{1500} \times 100$

So, Mass of $\left(NaOCl\right)$ $=\frac{1500\times 3.62}{100} g$

= $54.3g$

Conclusion

Mass of sodium hypochlorite $\left(NaOCl\right)$ is $54.3g$.