Interpretation:
The amount of gas is to be calculated at different pressure that is 110 kPa.
Concept Introduction:
Henry’s Law:
At a given temperature, the solubility of the gas in a liquid is directly proportional to the pressure above the liquid:
Where S represents solubility while P represents pressure.
After cross multiplying, the equation can be written as;
Where
S1 = Solubility of gas
S2 = Solubility at the new pressure
P1 = Initial Pressure
P2 = New Pressure
Answer to Problem 36PP
3g of gas is dissolved at 110 kPa.
Explanation of Solution
Given information:
Mass of gas = 0.55 g
Volume =1 L
Initial pressure P1 = 20 kPa
New Pressure P2 = 110 kPa
At a given temperature, the solubility of the gas in a liquid is directly proportional to the pressure above the liquid:
Where S represents solubility while P represents pressure.
After cross multiplying, the equation can be written as;
Where,
S1 = Solubility of gas
S2 = Solubility at the new pressure
P1 = Initial Pressure
P2 = New Pressure
Write the explanation of solubility,
S1 = Solubility of gas=
=
=
As it can be seen from the equation,
Putting all the values in the equation:
So 3g of gas is dissolved at 110 kPa.
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Chemistry: Matter and Change
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