Chapter 14, Problem 73A

Interpretation Introduction

Interpretation:

The number of moles of BaS needs to be calculated.

Concept introduction:

Molarity: Molarity is defined as the number of moles of solute present in one litre of the solution In expression, $\mathrm{Molarity}ofthesolution=\frac{Numberofmolesof the solute}{ Volume of the solution(inlitre)}$

Answer to Problem 73A

15 moles of BaS used to make 1.5 × 10³mL of a 10.0 M solution.

Explanation of Solution

Data information:

Volume of BaSsolution = 1.5 × 10³mL = 1.5 L

Molarity of BaS solution = 10.0 M

Write the expression for Molality of the solution.

$Molarityofthesolution=\frac{Numberofmolesof the solute}{ Volume of the solution(inlitre)}$

Calculate the number of Moles of $\mathrm{BaS}$

$\begin{array}{l}Numberofmolesof BaS=Volume of BaS solution\times MolarityofBaSsolution\\ Numberofmolesof BaS=1.5L\times 10.0mol/L=15mole\end{array}$

Thus, 15 moles of BaS used to make 1.5 × 10³mL of a 10.0 M solution.