Interpretation:
Amount of CaCl2 is to be calculated to prepare 1.0 L of 0.10 M CaCl2 solution.
Concept Introduction:
The concentrations of solutions are expressed in different ways. All of them are involved in the quantity of solute and the quantity of solution or solvent. Among them, molarity is widely used to express the concentration of a solution. Molarity: Molarity is defined as the number of moles of solute present in one liter of the solution.
In expression, Molarity of solution=Number of moles of soluteVolume of solution(in litre)
Again Number of moles of solute=Mass of solutemolecular weight of solute
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Answer to Problem 20PP
11.1gm of CaCl2 is needed to make 1.0L of 0.10M CaCl2 solution.
Explanation of Solution
Given information:
The molarity of CaCl2 solution = 0.10
Volume of CaCl2 solution = 1.0 L
In expression, Molarity of solution=Number of moles of soluteVolume of solution(in litre)
Molarity of CaCl2solution=Number of moles of CaCl2Volume of CaCl2solution(in litre)
Number of moles of CaCl2 = 0.10 M × 1.0 L
= 0.10 (mol/litre) × 1.0 litre = 0.10
Again Number of moles of solute=Mass of solutemolecular weight of solute
=Mass of CaCl2Molecular weight of CaCl2
= 0.10
i.e, Mass of CaCl2 = 110.98 (gm/mol) × 0.10 mol (Molecular weight of CaCl2 = 110.98 gm/mol)
= 11.1 gm
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