Chapter 14.2, Problem 14PP

Interpretation Introduction

Interpretation:

Percent by volume of isopropyl alcohol in a solution containing $24mL$ isopropyl alcohol in $1.1L$ of water is to be calculated.

Concept introduction:

The concentrations of solutions are expressed in different ways, all of them involved in the quantity of solute and the quantity of solution or solvent. Among them, Volume/volume percentage (v/V percent) is used to express the concentration of solution.

Volume/volume percentage (v/V percent):

Percent by volume usually describes solutions in which both solute and solvent are liquids. It is expressed as the ratio of the volume of the solute to the total volume of the solution multiplied by 100.

In expression (v/V) % $=\frac{Volumeof\text{solute}}{Volumeofsolution}\times 100$

Answer to Problem 14PP

Percent by volume of isopropyl alcohol in a solution having $24mL$ isopropyl alcohol in $1.1L$ of water is $2.13\%$

Explanation:

(v/V) % $\text{=}\frac{\text{Volume}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}}\text{×100}$

If we write in equation,

Percent by volume of isopropyl alcohol $=\frac{Volumeofisopropylalcohol}{Volumeofsolution}\times 100$

Data given:

Volume of isopropyl alcohol = $24mL$

Volume of water = $1.1L$

= $1100mL$

So, volume of the solution = volume of isopropyl alcohol + volume of water

$\begin{array}{c} =\left(24+1100\right)mL\\ =1124mL\end{array}$

Percent by volume of isopropyl alcohol = $=\frac{Volumeofisopropylalcohol}{Volumeofsolution}\times 100$

$=\frac{22}{114}\times 100$

= $2.13\%$

Percent by volume of isopropyl alcohol in a solution having $24mL$ isopropyl alcohol in $1.1L$ of water is $2.13\%$

Explanation of Solution

(v/V) % $\text{=}\frac{\text{Volume}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}}\text{×100}$

If we write in equation,

Percent by volume of isopropyl alcohol $=\frac{Volumeofisopropylalcohol}{Volumeofsolution}\times 100$

Data given:

Volume of isopropyl alcohol = $24mL$

Volume of water = $1.1L$

= $1100mL$

So, volume of the solution = volume of isopropyl alcohol + volume of water

$\begin{array}{c} =\left(24+1100\right)mL\\ =1124mL\end{array}$

Percent by volume of isopropyl alcohol = $=\frac{Volumeofisopropylalcohol}{Volumeofsolution}\times 100$

$=\frac{22}{114}\times 100$

= $2.13\%$

Conclusion

Percent by volume of isopropyl alcohol in a solution having $24mL$ isopropyl alcohol in $1.1L$ of water is $2.13\%$