Chapter 14.3, Problem 38PP

Interpretation Introduction

Interpretation:

Amount of gas is to be calculated when pressure was raised to 10 atm

Concept introduction:

Henry’s Law:

At a given temperature, solubility of the gas in a liquid is directly proportional to the pressure above the liquid :

$\frac{S_1}{P_1}=\frac{S_2}{P_2}$

Where, S represents solubility while P represents pressure.

After cross multiplying, the equation can be written as;

S₁ P₂ = S₂ P₁

S₁ = Solubility of gas S₂ = Solubility at new pressure

P₁ = Pressure P₂ = New Pressure

Answer to Problem 38PP

1.26 g of gas dissolved in 1L of solution when pressure increased to 10 atm.

At a given temperature, solubility of the gas in a liquid is directly proportional to the pressure above the liquid:

$\frac{S_1}{P_1}=\frac{S_2}{P_2}$

Where, S represents solubility while P represents pressure.

After cross multiplying, the equation can be written as;

S₁ P₂ = S₂ P₁

S₁ = Solubility of gas S₂ = Solubility at new pressure

P₁ = Pressure P₂ = New Pressure

Given,

Volume=1 L

S₁=0.52g/L

P₁₌7atm

${\mathrm{P}}_{2=}{P}_1+10$

$\begin{array}{l}=7+10\\ =17\end{array}$

As it can be seen from the equation,

= S₁ P₂ = S₂ P₁ S₂₌$\frac{S_1{P}_2}{P_1}$

Putting all the values in the equation:

= $\frac{0.52\times 7}{17}$

=1.26g/L

As, 1.26 g of gas dissolved in 1L of solution when pressure increased to 10 atm.

Explanation of Solution

At a given temperature, solubility of the gas in a liquid is directly proportional to the pressure above the liquid:

$\frac{S_1}{P_1}=\frac{S_2}{P_2}$

Where, S represents solubility while P represents pressure.

After cross multiplying, the equation can be written as;

S₁ P₂ = S₂ P₁

S₁ = Solubility of gas S₂ = Solubility at new pressure

P₁ = Pressure P₂ = New Pressure

Given,

Volume=1 L

S₁=0.52g/L

P₁₌7atm

${\mathrm{P}}_{2=}{P}_1+10$

$\begin{array}{l}=7+10\\ =17\end{array}$

As it can be seen from the equation,

= S₁ P₂ = S₂ P₁ S₂₌$\frac{S_1{P}_2}{P_1}$

Putting all the values in the equation:

= $\frac{0.52\times 7}{17}$

=1.26g/L

As, 1.26 g of gas dissolved in 1L of solution when pressure increased to 10 atm.