Chapter 14, Problem 18STP

Interpretation Introduction

Interpretation:

The electro negativity difference in the compound Li₂O have to be calculated.

Concept introduction:

The electro negativity of an element is defined as a measure of the tendency of an atom in a molecule to attract, to it self, the electrons in a chemical bond. Thus in a hetero-nuclear bond between two different atoms, the electrons of the bond will shift more towards that atom with higher electro negativity.

Answer to Problem 18STP

The correct answer is B. The electro negativity difference in the compound Li₂O is 2.46.

From the electro negativity data of the elements in the above table we see that,

The electro negativity of Li is 0.98. Li is an alkali metal and it is electropositive in nature. Thus Li shows lower electro negativity value.

The element ‘O’ shows higher electro negativity andthe value is 3.44.

Electronegativity difference in Li₂O = (Electronegativity of O - Electronegativityof Li)

The electro negativity difference in the compound Li₂O is 2.46.

Reasons for incorrect options:

As, it is already calculated that the electro negativity difference in the compound Li₂O is 2.46.

Answer isB.

That means other options that is,

A. 1.48

C. 3.4

D. 4.42

E. 5.19are found to be incorrect.

Explanation of Solution

From the electro negativity data of the elements in the above table we see that,

The electro negativity of Li is 0.98. Li is an alkali metal and it is electropositive in nature. Thus Li shows lower electro negativity value.

The element ‘O’ shows higher electro negativity andthe value is 3.44.

Electronegativity difference in Li₂O = (Electronegativity of O - Electronegativityof Li)

The electro negativity difference in the compound Li₂O is 2.46.

Conclusion

Reasons for incorrect options:

As, it is already calculated that the electro negativity difference in the compound Li₂O is 2.46.

Answer isB.

That means other options that is,

A. 1.48

C. 3.4

D. 4.42

E. 5.19are found to be incorrect.