Chapter 14, Problem 94A

Interpretation Introduction

Interpretation:

The solubility is to be calculated for a given pressure.

Concept introduction:

Solubility: Solubility can be expressed as maximum amount of solute that can dissolve in a known amount of solvent at a given temperature and pressure.

Henry’s Law: In liquid, the solubility of a gas is directly proportional to its pressure above the liquid at given temperature.

Answer to Problem 94A

The solubility of CO₂ in open drink is $4.0\times 10^{-4}gm/litre$.

Explanation of Solution

Given information:

$S_1=0.12mol/litre$

$P_1=4.0\mathrm{atm}$

$P_2=3.0\times {10}^{-4}\mathrm{atm}$

The expression of Henry’s Law is $\frac{S_1}{P_1}=\frac{S_2}{P_2}$

The solubility of a gas is S₁ at P₁ pressure and S₂ at pressure P₂.

$\begin{array}{c}\frac{S_1}{P_1}=\frac{S_2}{P_2}\\ S_2=\frac{S_1\times P_2}{P_1}\\ {\mathrm{S}}_2=\frac{0.12mol/litre\times 3.0\times 10^{-4}atm}{4.0atm}\\ =9.0\times 10^{-6}mol/litre\end{array}$

1 mol CO₂ is equal to 44 gm CO₂.

$\begin{array}{c}ThesolubilityofC{O}_2\text{}=9.0\times 10^{-6}mol/litre\times 44gm/mol\\ =4.0\times 10^{-4}gm/litre\end{array}$