Chapter 14, Problem 121A

Interpretation Introduction

Interpretation:

The volume of argon atomhave to be calculated.

Concept introduction:

$\mathrm{Volume}ofthesphere=V=\frac{4}{3}\pi r^3$

Answer to Problem 121A

Volume of argon atom 3.48 × 10-3 nm³.

Explanation of Solution

$\mathrm{Volume}ofthesphere=V=\frac{4}{3}\pi r^3$

Data given: The radius of an argon atom = 94 pm = 94 × 10-³nm

$\mathrm{Volu}\mathrm{me}ofargonatom=V=\frac{4}{3}\pi r^3$

$=\frac{4}{3}\times 3.14\times {(94\times 10^{-3}nm)}^3$

$=3.48\times 10^{-3}n{m}^3$