Chapter 14.2, Problem 11PP

Interpretation Introduction

Interpretation:

Mass of the solvent only in sodium hypochlorite $\left(NaOCl\right)$ solution is to be calculated where the percent by mass of sodium hypochlorite $\left(NaOCl\right)$ in bleach solution is $3.62\%$ and mass of the bleach solution is already calculated in previous question.

Concept introduction:

The concentration of solution is expressed in different ways, all of them involved in the quantity of solute and the quantity of solution or solvent. Among them, Mass percentage (w/W percent) is used to express the concentration of solution.

Mass percentage (w/W percent):

Percent by mass usually describes solutions in which solute is solid and solvent is liquid. It is expressed as the ratio of the mass of the solute to the mass of the solution multiplied by 100.

In expression, $\mathrm{Mass}percentage\left(w/W\right)\%=\frac{Massofsolute}{Massofsolution}\times 100$

(Mass of the solution = Mass of the solute + Mass of the solvent)

Answer to Problem 11PP

Mass of the solvent is $1445.7gm$.

Mass of the solution = Mass of the solute + Mass of the solvent

Data given: Mass of the bleach solution = $1500gm$

Mass of the solute $\left(NaOCl\right)$ = $54.3gm$

So, Mass of the solvent = Mass of the bleach solution - Mass of solute $\left(NaOCl\right)$

$\begin{array}{l} =\left(1500–54.3\right)gm\hfill \\ =1445.7gm\hfill \end{array}$

Mass of the solvent is $1445.7gm$.

Explanation of Solution

Mass of the solution = Mass of the solute + Mass of the solvent

Data given: Mass of the bleach solution = $1500gm$

Mass of the solute $\left(NaOCl\right)$ = $54.3gm$

So, Mass of the solvent = Mass of the bleach solution - Mass of solute $\left(NaOCl\right)$

$\begin{array}{l} =\left(1500–54.3\right)gm\hfill \\ =1445.7gm\hfill \end{array}$

Conclusion

Mass of the solvent is $1445.7gm$.