Chapter 14, Problem 77A

Interpretation Introduction

Interpretation:

The molarity of the diluted solution has to be calculated.

Concept Introduction:

The equation for dilution is

 $\begin{array}{l} M_1{V}_1=M_2{V}_2\hfill \end{array}$

$\begin{array}{l}Stock\hspace{0.17em}solution\hspace{0.17em}=\hspace{0.17em}Diluted\hspace{0.17em}solution\hfill \end{array}$

Concentrated solutions of known molarities are known as a stock solution.

Where,

M₁ = molarity of the stock solution   V₁ = volume of stock solution

M₂ = molarity of the diluted solution   V₂ = volume of diluted solution.

Answer to Problem 77A

The molarity ofdiluted solution is 0.88 M.

Explanation of Solution

Given information:

Molarity of the stock solution $M_1=4.0\text{ M}$

Volume of the stock solution $V_1 =55\text{ mL}$

Volume of dilutedsolution $V_2=250\text{ mL}$

Write the expression for Molality.

 $\begin{array}{l} M_1{V}_1=M_2{V}_2\hfill \end{array}$

$\begin{array}{l}Stock\hspace{0.17em}solution\hspace{0.17em}=\hspace{0.17em}Diluted\hspace{0.17em}solution\hfill \end{array}$

  $\begin{array}{l}Molarity\hspace{0.17em}of\hspace{0.17em}the\hspace{0.17em}diluted\hspace{0.17em}solution=M_2=\frac{M_1{V}_1}{V_2}\end{array}$

     $\begin{array}{c}{M}_2=\frac{4.0M\times 55mL}{250mL}=0.88M\end{array}$

The molarity of the diluted solution is 0.88 M.