A double-glazed window consists of two panes of glass, each of thickness t = 6 mm . The inside room temperature is T i = 20 ° C with h i = 7.7 W/m 2 ⋅ K , while the outside temperature is T o = − 10 ° C with h o = 25 W/m 2 ⋅ K . The gap between the glass sheets is of thickness L = 5 mm and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from ε = 0.95 to ε = 0.05 . Determine the heat flux through the window for case ε 1 = ε 2 = 0.95 , case 2: ε 1 = ε 2 = 0.05 , and case 3: ε 1 = 0.05 , ε 2 = 0.95 . Consider either air or argon of thermal conductivity k Ar = 17.7 × 10 − 3 W/m ⋅ K to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
A double-glazed window consists of two panes of glass, each of thickness t = 6 mm . The inside room temperature is T i = 20 ° C with h i = 7.7 W/m 2 ⋅ K , while the outside temperature is T o = − 10 ° C with h o = 25 W/m 2 ⋅ K . The gap between the glass sheets is of thickness L = 5 mm and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from ε = 0.95 to ε = 0.05 . Determine the heat flux through the window for case ε 1 = ε 2 = 0.95 , case 2: ε 1 = ε 2 = 0.05 , and case 3: ε 1 = 0.05 , ε 2 = 0.95 . Consider either air or argon of thermal conductivity k Ar = 17.7 × 10 − 3 W/m ⋅ K to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
Solution Summary: The author describes the heat flux through the window for the various cases. The length of windows is L=5mm.
A double-glazed window consists of two panes of glass, each of thickness
t
=
6
mm
. The inside room temperature is
T
i
=
20
°
C
with
h
i
=
7.7
W/m
2
⋅
K
, while the outside temperature is
T
o
=
−
10
°
C
with
h
o
=
25
W/m
2
⋅
K
. The gap between the glass sheets is of thickness
L
=
5
mm
and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from
ε
=
0.95
to
ε
=
0.05
. Determine the heat flux through the window for case
ε
1
=
ε
2
=
0.95
, case 2:
ε
1
=
ε
2
=
0.05
, and case 3:
ε
1
=
0.05
,
ε
2
=
0.95
. Consider either air or argon of thermal conductivity
k
Ar
=
17.7
×
10
−
3
W/m
⋅
K
to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
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