A double-glazed window consists of two panes of glass, each of thickness t = 6 mm . The inside room temperature is T i = 20 ° C with h i = 7.7 W/m 2 ⋅ K , while the outside temperature is T o = − 10 ° C with h o = 25 W/m 2 ⋅ K . The gap between the glass sheets is of thickness L = 5 mm and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from ε = 0.95 to ε = 0.05 . Determine the heat flux through the window for case ε 1 = ε 2 = 0.95 , case 2: ε 1 = ε 2 = 0.05 , and case 3: ε 1 = 0.05 , ε 2 = 0.95 . Consider either air or argon of thermal conductivity k Ar = 17.7 × 10 − 3 W/m ⋅ K to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
A double-glazed window consists of two panes of glass, each of thickness t = 6 mm . The inside room temperature is T i = 20 ° C with h i = 7.7 W/m 2 ⋅ K , while the outside temperature is T o = − 10 ° C with h o = 25 W/m 2 ⋅ K . The gap between the glass sheets is of thickness L = 5 mm and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from ε = 0.95 to ε = 0.05 . Determine the heat flux through the window for case ε 1 = ε 2 = 0.95 , case 2: ε 1 = ε 2 = 0.05 , and case 3: ε 1 = 0.05 , ε 2 = 0.95 . Consider either air or argon of thermal conductivity k Ar = 17.7 × 10 − 3 W/m ⋅ K to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
Solution Summary: The author describes the heat flux through the window for the various cases. The length of windows is L=5mm.
A double-glazed window consists of two panes of glass, each of thickness
t
=
6
mm
. The inside room temperature is
T
i
=
20
°
C
with
h
i
=
7.7
W/m
2
⋅
K
, while the outside temperature is
T
o
=
−
10
°
C
with
h
o
=
25
W/m
2
⋅
K
. The gap between the glass sheets is of thickness
L
=
5
mm
and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from
ε
=
0.95
to
ε
=
0.05
. Determine the heat flux through the window for case
ε
1
=
ε
2
=
0.95
, case 2:
ε
1
=
ε
2
=
0.05
, and case 3:
ε
1
=
0.05
,
ε
2
=
0.95
. Consider either air or argon of thermal conductivity
k
Ar
=
17.7
×
10
−
3
W/m
⋅
K
to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
Q In a test on a two.. strok, heavy oil, marine engine, the following observations were
made: Oil consumption, 4.05 kg/h; Calorific value of oil, 43000kj/kg; het brake
load 579N; Mean brake diameter, 1m; mean effective pressure 275 kN/m²; cylinder diameter
0.20m; stroke, 0.250m; speed, 360 rpm.
Calculate
the mechanical efficiency the indicated thermal efficiency Y
The brake thermal efficiency and the quantity of jacket water required per
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امتصت
minute if 30% of the energy supplied by the fuel is absorbed by this water.
Permissible rise in temperature is 20k and specific heat capacity of water-4.1868 kj
Answers [84.2%, 26-8%, 22.6%, 8.33 kg/min]
kg.k
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Q78 A four cylinder, four-stroke Petrol engine has a compression ratio of 6 to 1. A test on
this engine gave the following results;
Net brake load = 20 kg, effective brake arm = 0.5 m, indicated mep=6*105 N/m², engine
speed 2400 rpm, fuel consumption = 10 kg/h, Calorific value of the fuel = 44000kj/kg,
Cylinder bore 86 mm, engine stroke-100mm.
ข่าวล
Calculate: the mechanical efficiency, ⑥the brake thermal efficiency the relative
efficiency assuming the engine works on the Constant volume cycle and that 8-1.4 forair
⑧The brake mean effective pressure.
Answers 1 88.4%, 48/5-35 × 105 N/m² 1
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For the instant represented, crank OB has a clockwise angular velocity w = 1.22 rad/sec and is passing the horizontal position.
Determine the corresponding magnitudes of the velocity of the guide roller A in the 22° slot and the velocity of point C midway
between A and B.
15"
7
C. 32"
AO
22%
B
Answers:
VA =
VC =
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