Coatings applied to long metallic strips are cured by installing the strips along the walls of a long oven of square cross section. Thermal conditions in the oven are maintained by a long silicon carbide rod (heating element), which is of diameter D = 20 mm and is operated at T 1 = 1700 K . Each of two strips on one side wall has the same orientation relative to the rod ( s 1 = 60 mm , s 2 = 20 mm , L = 80 mm ) and is operated at T 2 = 600 K . All surfaces are diffuse and gray with ε 1 = 0.9 and ε 2 = 0.4 . Assuming the oven to be well insulated al all but the strip surfaces and neglecting convection effects, determine the heater power requirement per unit length (W/m).
Coatings applied to long metallic strips are cured by installing the strips along the walls of a long oven of square cross section. Thermal conditions in the oven are maintained by a long silicon carbide rod (heating element), which is of diameter D = 20 mm and is operated at T 1 = 1700 K . Each of two strips on one side wall has the same orientation relative to the rod ( s 1 = 60 mm , s 2 = 20 mm , L = 80 mm ) and is operated at T 2 = 600 K . All surfaces are diffuse and gray with ε 1 = 0.9 and ε 2 = 0.4 . Assuming the oven to be well insulated al all but the strip surfaces and neglecting convection effects, determine the heater power requirement per unit length (W/m).
Solution Summary: The author explains the heater power requirement per unit length, the distance between heating element and strip, and the expression for reciprocity theorem.
Coatings applied to long metallic strips are cured by installing the strips along the walls of a long oven of square cross section.
Thermal conditions in the oven are maintained by a long silicon carbide rod (heating element), which is of diameter
D
=
20
mm
and is operated at
T
1
=
1700
K
. Each of two strips on one side wall has the same orientation relative to the rod
(
s
1
=
60
mm
,
s
2
=
20
mm
,
L
=
80
mm
)
and is operated at
T
2
=
600
K
. All surfaces are diffuse and gray with
ε
1
=
0.9
and
ε
2
=
0.4
. Assuming the oven to be well insulated al all but the strip surfaces and neglecting convection effects, determine the heater power requirement per unit length (W/m).
[2] An array of electronic chips is mounted within a sealed rectangular enclosure, and cooling is implemented by
attaching an aluminum heat sink (k = 180 W/m K). The base of the heat sink has dimensions of w1 = W2 = 100 mm,
while the 6 fins are of thickness t = 10 mm and pitch S = 18 mm. The fin length is Lr = 50 mm, and the base of the heat
sink has a thickness of Lb = 10 mm.
L
-Chips
Water u T
Electronic
package,
P
elec
If cooling is implemented by water flow through the heat sink, with uo = 3 m/s and To =
temperature Tb of the heat sink when power dissipation by the chips is Pelec = 1800 W? The average convection
coefficient for surfaces of the fins and the exposed base may be estimated by assuming parallel flow over a flat plate.
Properties of the water may be approximated as k = 0.62 W/m-K, p = 995 kg/m3, Cp = 4178 J/kg-K, v = 7.73 x 10-7 m2/s,
and Pr = 5.2.
17°C, what is the base
a.) Base temperature.
А. 37.8°C
B. 43.9°C
С. 31.4°С
D. 46.2°C
6. Make a diagram and show the step-by-step process. Do not use shortcut methods. Make it as detailed as it can be.
Encode (not hand-written)! DO NOT COPY CHEGG'S ANSWER
A cold storage room has a wall consists of an inside finish of 0.60 in cement plaster(k = 0.67), two layers of corkboard each 2.5 in thick (k = 0.03) and an outside layer of building tile. The value of U for the entire wall is 0.058, the internal air filmcoefficient is 1.65, the inner temperature is 23°F and the outside temperature is85°F. Calculate the heat flow through the unit wall area, Btu/hr.ft2A. 1.47 B. 2.47 C. 3.47 D. 4.47
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