Chapter 4.4, Problem 2E

To determine

To find LCD.

Answer to Problem 2E

  $\frac{7}{12}$ is greater than $\frac{4}{7}$ .

Explanation of Solution

Given information: $\frac{7}{12},\frac{4}{7}$

Formula Used: Factorisation

Calculation:

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 7 and 12 is 84

So , denominator of both fractions 84.

  $\frac{4\times 12}{7\times 12}=\frac{48}{84}$

  $\frac{7\times 7}{12\times 7}=\frac{49}{84}$

  $\frac{48}{84}<\frac{49}{84}$

So, $\frac{7}{12}$ is greater than $\frac{4}{7}$ .