An image processor considered a 750×750 pixels large subset of an image and converted it into gray-scale, resulting in matrix gIn - a false-color visualization of gIn is shown in the top-left below. He prepared a two-dim. box filter f1 as a 25×25 matrix with only the 5×5 values in the middle being non-zero – this filter is shown in the top-middle position below. He then convolved £1 with itself to get £2, before convolving £2 with itself to get f3. In both of the steps, he maintained the 25×25 size. Next, he convolved gIn with £3 to get gl. Which of the six panels below shows g1? Argue by explaining all the steps, so far: What did the image processor do when preparing ₤3? What image processing operation (from gin to g1) did he prepare and what's the effect that can be seen? Next, he convolved the rows of f3 with filter 1/2 (-1, 8, 0, -8, 1) to get f4 - you find a visualization of filter f 4 below. He then convolved gIn with f4 to get g2 and you can find the result shown below. What happened and why? Explain the resulting effect as seen in the false-color visualization of g2. Next, he convolved the columns of £3 with (-1, 8, 0, -8, 1) to get £5, which he then used in a convolution of gin with f5 to get g3. Next he computed g4 = (92.^2+93.^2). (1/2) and you ^ can find a false-color visualization of g4 below. What did the image processor achieve and how? 0 100 200 300 400 500 600 700 100 treatment planning, .. 250 200 300 400 500 600 700 100 200 300 400 500 600 700 100 planning. 200 300 400 500 600 700 filter 11: box 100 200 300 400 500 600 700 30 100 treatment planning, 25 200 0.04- 200 0.035- 0.03- 300 150 0.025 0.02- 400 100 0.015 500 0.01 600 0.005 0 30 4 700 0 100 200 300 400 500 100 treatment planning. 200 300 400 500 600 20 15 10 600 700 250 700 0 200 150 100 What if the image processor also did the following: prepare a smaller box filter h1 - also in a 25×25 matrix, but with only the 3×3 values in the middle being non-zero. After constructing h3 as above - h2 = hlohl and h3h2o h2 - he'd get h4 = f3 h3. When convolving gIn with h4, what result would he get? How would the resulting image look like?

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.2: Guassian Elimination And Matrix Methods
Problem 87E
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An image processor considered a 750×750 pixels large subset of an image and converted it into gray-scale,
resulting in matrix gIn - a false-color visualization of gIn is shown in the top-left below. He prepared a
two-dim. box filter f1 as a 25×25 matrix with only the 5×5 values in the middle being non-zero – this filter
is shown in the top-middle position below. He then convolved £1 with itself to get £2, before convolving £2
with itself to get f3. In both of the steps, he maintained the 25×25 size.
Next, he convolved gIn with £3 to get gl. Which of the six panels below shows g1? Argue by explaining
all the steps, so far: What did the image processor do when preparing ₤3? What image processing operation
(from gin to g1) did he prepare and what's the effect that can be seen?
Next, he convolved the rows of f3 with filter 1/2 (-1, 8, 0, -8, 1) to get f4 - you find a visualization of
filter f 4 below. He then convolved gIn with f4 to get g2 and you can find the result shown below. What
happened and why? Explain the resulting effect as seen in the false-color visualization of g2.
Next, he convolved the columns of £3 with
(-1, 8, 0, -8, 1) to get £5, which he then used in a
convolution of gin with f5 to get g3. Next he computed g4 = (92.^2+93.^2). (1/2) and you
^
can find a false-color visualization of g4 below. What did the image processor achieve and how?
0 100 200 300 400 500 600 700
100
treatment
planning, ..
250
200
300
400
500
600
700
100 200 300 400 500 600 700
100
planning.
200
300
400
500
600
700
filter 11: box
100 200 300 400 500 600 700
30
100
treatment
planning,
25
200
0.04-
200
0.035-
0.03-
300
150
0.025
0.02-
400
100
0.015
500
0.01
600
0.005
0
30
4
700
0 100 200 300 400 500
100
treatment
planning.
200
300
400
500
600
20
15
10
600
700
250
700
0
200
150
100
What if the image processor also did the following: prepare a smaller box filter h1 - also in a 25×25 matrix,
but with only the 3×3 values in the middle being non-zero. After constructing h3 as above - h2 = hlohl
and h3h2o h2 - he'd get h4 = f3 h3. When convolving gIn with h4, what result would he
get? How would the resulting image look like?
Transcribed Image Text:An image processor considered a 750×750 pixels large subset of an image and converted it into gray-scale, resulting in matrix gIn - a false-color visualization of gIn is shown in the top-left below. He prepared a two-dim. box filter f1 as a 25×25 matrix with only the 5×5 values in the middle being non-zero – this filter is shown in the top-middle position below. He then convolved £1 with itself to get £2, before convolving £2 with itself to get f3. In both of the steps, he maintained the 25×25 size. Next, he convolved gIn with £3 to get gl. Which of the six panels below shows g1? Argue by explaining all the steps, so far: What did the image processor do when preparing ₤3? What image processing operation (from gin to g1) did he prepare and what's the effect that can be seen? Next, he convolved the rows of f3 with filter 1/2 (-1, 8, 0, -8, 1) to get f4 - you find a visualization of filter f 4 below. He then convolved gIn with f4 to get g2 and you can find the result shown below. What happened and why? Explain the resulting effect as seen in the false-color visualization of g2. Next, he convolved the columns of £3 with (-1, 8, 0, -8, 1) to get £5, which he then used in a convolution of gin with f5 to get g3. Next he computed g4 = (92.^2+93.^2). (1/2) and you ^ can find a false-color visualization of g4 below. What did the image processor achieve and how? 0 100 200 300 400 500 600 700 100 treatment planning, .. 250 200 300 400 500 600 700 100 200 300 400 500 600 700 100 planning. 200 300 400 500 600 700 filter 11: box 100 200 300 400 500 600 700 30 100 treatment planning, 25 200 0.04- 200 0.035- 0.03- 300 150 0.025 0.02- 400 100 0.015 500 0.01 600 0.005 0 30 4 700 0 100 200 300 400 500 100 treatment planning. 200 300 400 500 600 20 15 10 600 700 250 700 0 200 150 100 What if the image processor also did the following: prepare a smaller box filter h1 - also in a 25×25 matrix, but with only the 3×3 values in the middle being non-zero. After constructing h3 as above - h2 = hlohl and h3h2o h2 - he'd get h4 = f3 h3. When convolving gIn with h4, what result would he get? How would the resulting image look like?
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