Chapter 4.4, Problem 45E

To determine

To find the LCD

Answer to Problem 45E

  $\frac{8}{21}$ is greater than $\frac{5}{18}$ .

Explanation of Solution

Given information: $\frac{5}{18},\frac{8}{21}$

Formula Used: Factorisation

Calculation:

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 18 and 21 is 126

So , denominator of both fractions 126.

  $\frac{5\times 7}{18\times 7}=\frac{35}{126}$

  $\frac{8\times 6}{21\times 6}=\frac{48}{126}$

  $\frac{48}{126}>\frac{35}{126}$

So, $\frac{8}{21}$ is greater than $\frac{5}{18}$ .