Chapter 4.4, Problem 54E

To determine

To order the number from least to greatest.

Answer to Problem 54E

  $1\frac{1}{3}<1\frac{13}{33}<\frac{10}{7},$ .

Explanation of Solution

Given information: $1\frac{1}{3},\frac{10}{7},1\frac{13}{33}$

Formula Used: Factorisation

Calculation:

  $1\frac{1}{3}=\frac{4}{3}$ and $1\frac{13}{33}=\frac{46}{33}$

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 3, 7 and 33 is 231

So , denominator of both fractions 231.

  $\frac{4\times 77}{3\times 77}=\frac{308}{231}$

  $\frac{10\times 33}{7\times 33}=\frac{330}{231}$

  $\frac{46\times 7}{33\times 7}=\frac{322}{231}$

  $\frac{308}{231}<\frac{322}{231}<\frac{330}{231}$

So, $1\frac{1}{3}<1\frac{13}{33}<\frac{10}{7},$ .