Chapter 4.4, Problem 48E

To determine

To order the number from least to greatest.

Answer to Problem 48E

  $\frac{13}{4}<\frac{27}{8}<3\frac{1}{2}$ .

Explanation of Solution

Given information: $\frac{13}{4},3\frac{1}{2},\frac{27}{8}$

Formula Used: Factorisation

Calculation:

  $3\frac{1}{2}=\frac{7}{2}$

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 4, 2 and 8 is 8

So , denominator of both fractions 8.

  $\frac{13\times 2}{4\times 2}=\frac{26}{8}$

  $\frac{7\times 4}{2\times 4}=\frac{28}{8}$

  $\frac{27\times 1}{8\times 1}=\frac{27}{8}$

  $\frac{26}{8}<\frac{27}{8}<\frac{28}{8}$

So, $\frac{13}{4}<\frac{27}{8}<3\frac{1}{2}$ .