Chapter 4.4, Problem 61E

To determine

To findLCM.

Answer to Problem 61E

LCM = $364a{b}^2{c}^3$

Explanation of Solution

Given information: $26a{b}^2,28a{c}^3$

Formula Used: Factorisation

Calculation:

The least common multiple of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

  $26a{b}^2=2\times 13\times a\times b\times b$

  $28a{c}^3=2\times 2\times 7\times a\times c\times c\times c$

LCM = $2\times 2\times 7\times 13\times a\times b\times b\times c\times c\times c$

LCM = $364a{b}^2{c}^3$