Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 4.5, Problem 66E

To determine

To find sum or difference of −14+98 .

Expert Solution & Answer

Answer to Problem 66E

Explanation of Solution

Given information: −14+98

This answer shall be derived using the negative and positive signs. If there is addition or subtraction of two numbers with different signs, subtract the numbers having opposite signs. The final answer shall have a positive or negative sign on the basis of the sign that the larger had, while calculated.

Calculation:

Given, −14+98

=98−14 Here, 98 is the larger number, and it is of positive sign. The smaller number is −14 . Hence two is subtracted.

=84 This a positive value since 98>14

Chapter 4.5, Problem 65E

Chapter 4.5, Problem 67E

Chapter 4 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 4.1 - Prob. 1C Ch. 4.1 - Prob. 2C Ch. 4.1 - Prob. 3C Ch. 4.1 - Prob. 4C Ch. 4.1 - Prob. 5C Ch. 4.1 - Prob. 6C Ch. 4.1 - Prob. 7C Ch. 4.1 - Prob. 8C Ch. 4.1 - Prob. 9C Ch. 4.1 - Prob. 10C

Ch. 4.1 - Prob. 11C Ch. 4.1 - Prob. 12C Ch. 4.1 - Prob. 13C Ch. 4.1 - Prob. 14C Ch. 4.1 - Prob. 15C Ch. 4.1 - Prob. 16C Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E Ch. 4.1 - Prob. 7E Ch. 4.1 - Prob. 8E Ch. 4.1 - Prob. 9E Ch. 4.1 - Prob. 10E Ch. 4.1 - Prob. 11E Ch. 4.1 - Prob. 12E Ch. 4.1 - Prob. 13E Ch. 4.1 - Prob. 14E Ch. 4.1 - Prob. 15E Ch. 4.1 - Prob. 16E Ch. 4.1 - Prob. 17E Ch. 4.1 - Prob. 18E Ch. 4.1 - Prob. 19E Ch. 4.1 - Prob. 20E Ch. 4.1 - Prob. 21E Ch. 4.1 - Prob. 22E Ch. 4.1 - Prob. 23E Ch. 4.1 - Prob. 24E Ch. 4.1 - Prob. 25E Ch. 4.1 - Prob. 26E Ch. 4.1 - Prob. 27E Ch. 4.1 - Prob. 28E Ch. 4.1 - Prob. 29E Ch. 4.1 - Prob. 30E Ch. 4.1 - Prob. 31E Ch. 4.1 - Prob. 32E Ch. 4.1 - Prob. 33E Ch. 4.1 - Prob. 34E Ch. 4.1 - Prob. 35E Ch. 4.1 - Prob. 36E Ch. 4.1 - Prob. 37E Ch. 4.1 - Prob. 38E Ch. 4.1 - Prob. 39E Ch. 4.1 - Prob. 40E Ch. 4.1 - Prob. 41E Ch. 4.1 - Prob. 42E Ch. 4.1 - Prob. 43E Ch. 4.1 - Prob. 44E Ch. 4.1 - 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Prob. 28E Ch. 4.3 - Prob. 29E Ch. 4.3 - Prob. 30E Ch. 4.3 - Prob. 31E Ch. 4.3 - Prob. 32E Ch. 4.3 - Prob. 33E Ch. 4.3 - Prob. 34E Ch. 4.3 - Prob. 35E Ch. 4.3 - Prob. 36E Ch. 4.3 - Prob. 37E Ch. 4.3 - Prob. 38E Ch. 4.3 - Prob. 39E Ch. 4.3 - Prob. 40E Ch. 4.3 - Prob. 41E Ch. 4.3 - Prob. 42E Ch. 4.3 - Prob. 43E Ch. 4.3 - Prob. 44E Ch. 4.3 - Prob. 45E Ch. 4.3 - Prob. 46E Ch. 4.3 - Prob. 47E Ch. 4.3 - Prob. 48E Ch. 4.3 - Prob. 49E Ch. 4.3 - Prob. 50E Ch. 4.3 - Prob. 51E Ch. 4.3 - Prob. 52E Ch. 4.3 - Prob. 53E Ch. 4.3 - Prob. 54E Ch. 4.3 - Prob. 55E Ch. 4.3 - Prob. 56E Ch. 4.3 - Prob. 57E Ch. 4.3 - Prob. 58E Ch. 4.3 - Prob. 59E Ch. 4.3 - Prob. 60E Ch. 4.3 - Prob. 61E Ch. 4.3 - Prob. 62E Ch. 4.3 - Prob. 63E Ch. 4.3 - Prob. 64E Ch. 4.3 - Prob. 65E Ch. 4.4 - Prob. 1C Ch. 4.4 - Prob. 2C Ch. 4.4 - Prob. 3C Ch. 4.4 - Prob. 4C Ch. 4.4 - Prob. 5C Ch. 4.4 - Prob. 6C Ch. 4.4 - Prob. 7C Ch. 4.4 - Prob. 8C Ch. 4.4 - Prob. 9C Ch. 4.4 - Prob. 10C Ch. 4.4 - Prob. 11C Ch. 4.4 - Prob. 12C Ch. 4.4 - Prob. 1E Ch. 4.4 - 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Publisher:McGraw-Hill Education

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To find sum or difference of − 14 + 98 .

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To find sum or difference of −14+98 .

Answer to Problem 66E

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Chapter 4 Solutions

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