Chapter 4.4, Problem 40E

To determine

To find the LCD

Answer to Problem 40E

  $\frac{2}{3}$ is greater than $\frac{5}{8}$ .

Explanation of Solution

Given information: $\frac{2}{3},\frac{5}{8}$

Formula Used: Factorisation

Calculation:

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 3 and 8 is 24

So , denominator of both fractions 24.

  $\frac{2\times 8}{3\times 8}=\frac{16}{24}$

  $\frac{5\times 3}{8\times 3}=\frac{15}{24}$

  $\frac{16}{24}>\frac{15}{24}$

So, $\frac{2}{3}$ is greater than $\frac{5}{8}$ .