Chapter 4.4, Problem 46E

To determine

To find the LCD

Answer to Problem 46E

  $\frac{20}{63}$ is greater than $\frac{11}{42}$ .

Explanation of Solution

Given information: $\frac{11}{42},\frac{20}{63}$

Formula Used: Factorisation

Calculation:

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 42 and 63 is 126

So , denominator of both fractions 126.

  $\frac{11\times 3}{42\times 3}=\frac{33}{126}$

  $\frac{20\times 2}{63\times 2}=\frac{40}{126}$

  $\frac{40}{126}>\frac{33}{126}$

So, $\frac{20}{63}$ is greater than $\frac{11}{42}$ .