Chapter 4.5, Problem 21E

To determine

Find the product.

Answer to Problem 21E

  ${(0.8)}^6$

Explanation of Solution

Given information: $\frac{{(0.8)}^{12}}{{(0.8)}^6}$

Formula Used: $\frac{a^x}{a^y}=a^{x-y}$

Calculation:

As the bases are same (0.8) and in division, the powers are subtracted.

  $\frac{{(0.8)}^{12}}{{(0.8)}^6}={(0.8)}^{12-6}$

  $\frac{{(0.8)}^{12}}{{(0.8)}^6}={(0.8)}^6$