(a)
To Analyze: The greatest number of minutes that could be in a space hour.
(a)

Answer to Problem 49E
25 hours
Explanation of Solution
Given: In the future, scientists may want to make a unit of time that is convenient for people living on both Earth and Mars. The new unit of time, called the space-hour, should divide evenly into the number of minutes in each planet’s day. Under the current Earth definition of minutes, Earth has 1440 minutes per day, and mars has approximately 1480 minutes per day.
In one hour is 60 minutes.
For Earth
So, Time in space-hour
For Mars
So, Time in space-hour
On mars number of minutes in space-hour is greater than Earth.
(b)
To Find: The space-hours on Earth and Mars.
(b)

Answer to Problem 49E
Earth
Mars
Explanation of Solution
Given: In the future, scientists may want to make a unit of time that is convenient for people living on both Earth and Mars. The new unit of time, called the space-hour, should divide evenly into the number of minutes in each planet’s day. Under the current Earth definition of minutes, Earth has 1440 minutes per day, and mars has approximately 1480 minutes per day.
In one hour is 60 minutes.
For Earth
So, Time in space-hour
For Mars
So, Time in space-hour
(C)
To find: The time travels from Earth to Mars.
(C)

Answer to Problem 49E
5145 hours
Explanation of Solution
Given: In the future, scientists may want to make a unit of time that is convenient for people living on both Earth and Mars. The new unit of time, called the space-hour, should divide evenly into the number of minutes in each planet’s day. Under the current Earth definition of minutes, Earth has 1440 minutes per day, and mars has approximately 1480 minutes per day.
A spacecraft that uses current technology can take 210 days to travel from Earth to Mars.
First find the mean of space-hours of both Earth and Mars.
The average of space-hour is 24.5 hour per day.
Total time to travel from Earth to Mars in 210 days.
Now convert into space-hours
In 1 day space−hour = 24.5 hours
In 210 days space-hours
Chapter 4 Solutions
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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