Chapter 4.4, Problem 53E

To determine

To order the number from least to greatest.

Answer to Problem 53E

  $\frac{43}{18}<\frac{12}{5}<2\frac{5}{12}$ .

Explanation of Solution

Given information: $\frac{12}{5},2\frac{5}{12},\frac{43}{18}$

Formula Used: Factorisation

Calculation:

  $2\frac{5}{12}=\frac{29}{12}$

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 5, 12 and 18 is 180

So , denominator of both fractions 180.

  $\frac{12\times 36}{5\times 36}=\frac{432}{180}$

  $\frac{29\times 15}{12\times 15}=\frac{435}{180}$

  $\frac{43\times 10}{18\times 10}=\frac{430}{180}$

  $\frac{430}{180}<\frac{432}{180}<\frac{435}{180}$

So, $\frac{43}{18}<\frac{12}{5}<2\frac{5}{12}$ .