Chapter 4.5, Problem 16C

To determine

Simplify.

Answer to Problem 16C

  $\frac{3y^5}{4}$

Explanation of Solution

Given information: $\frac{12y^2.y^8}{16y^5}$

Formula Used: $a^x.a^y=a^{x+y}$ and $\frac{a^x}{a^y}=a^{x-y}$

Calculation:

As the bases are same (y), and in division, the powers are subtracted.

  $\frac{12y^2.y^8}{16y^5}=\frac{3y^{2+8}}{4y^5}$

  $\frac{12y^2.y^8}{16y^5}=\frac{3y^{10-5}}{4}$

  $\frac{12y^2.y^8}{16y^5}=\frac{3y^5}{4}$