41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers . In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r 1 and r 2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n 1 , n 2 , and n 3 , the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated. Figure 35-42 Problems 41 through 52 n 1 n 2 n 3 Type L λ 51 1.40 1.46 1.75 min 210
41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers . In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r 1 and r 2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n 1 , n 2 , and n 3 , the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated. Figure 35-42 Problems 41 through 52 n 1 n 2 n 3 Type L λ 51 1.40 1.46 1.75 min 210
41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers. In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r1 and r2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n1, n2, and n3, the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated.
When violet light of wavelength 415 nm falls on a single slit, it creates a central diffraction peak that is 8.60
cm wide on a screen that is 2.80 m away.
Part A
How wide is the slit?
ΟΙ ΑΣΦ
?
D= 2.7.10-8
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Two complex values are z1=8 + 8i, z2=15 + 7 i. z1∗ and z2∗ are the complex conjugate values.
Any complex value can be expessed in the form of a+bi=reiθ. Find θ for (z1-z∗2)/z1+z2∗. Find r and θ for (z1−z2∗)z1z2∗ Please show all steps
Calculate the center of mass of the hollow cone
shown below. Clearly specify the origin and the
coordinate system you are using.
Z
r
Y
h
X
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