According to its directional distribution, solar radiation incident on the earth’s surface may be divided into two components. The direct component consists of parallel rays incident at a fixed zenith angle θ , while the diffuse component consists of radiation that may be approximated as being diffusely distributed with θ . Consider clear sky conditions for which the direct radiation is incident at 0 = 30 ∘ , with a total flux (based on an area that is normal to the rays) of q d i r " = 1000 W / m 2 , and the total intensity of the diffuse radiation is I d i f = 70 W / m 2 · s r . What is the total solar irradiation at the earth’ s surface?
According to its directional distribution, solar radiation incident on the earth’s surface may be divided into two components. The direct component consists of parallel rays incident at a fixed zenith angle θ , while the diffuse component consists of radiation that may be approximated as being diffusely distributed with θ . Consider clear sky conditions for which the direct radiation is incident at 0 = 30 ∘ , with a total flux (based on an area that is normal to the rays) of q d i r " = 1000 W / m 2 , and the total intensity of the diffuse radiation is I d i f = 70 W / m 2 · s r . What is the total solar irradiation at the earth’ s surface?
Solution Summary: The author calculates the total solar irradiation at the surface of earth as the sum of direct radiation and diffuse radiation.
According to its directional distribution, solar radiation incident on the earth’s surface may be divided into two components. The direct component consists of parallel rays incident at a fixed zenith angle
θ
, while the diffuse component consists of radiation that may be approximated as being diffusely distributed with
θ
.
Consider clear sky conditions for which the direct radiation is incident at
0
=
30
∘
, with a total flux (based on an area that is normal to the rays) of
q
d
i
r
"
=
1000
W
/
m
2
, and the total intensity of the diffuse radiation is
I
d
i
f
=
70
W
/
m
2
·
s
r
. What is the total solar irradiation at the earth’ s surface?
You can neglect radiation at the bottom of the plate; the bottom side of the plate has water flowing underneath it. Often, when dealing with liquids (rather than gases), one can neglect radiation because heat transfer due to convection is so much larger (liquids tend to have higher convection coefficient values than gases).
A small surface of area A1 = 5 cm? emits radiation as a blackbody, and part of the
radiation emitted by Ai strikes another small surface of area A2 = 8 cm? oriented as
shown in Fig. 4. If the rate at which radiation em itted by Ai that strikes A is measured
to be 274 x 106 W, determine
i.
the intensity of the radiation emitted by A1, and
the temperature of A1.
ji.
Az = 8 cm?
02 = 40°
10, = 55°
r = 80 cm
A = 5 cm?
Fig 4
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