A thermograph is a device responding to the radiant power from the scene, which reaches its radiation detector within the spectral region 9 − 12 μ m . The thermograph provides an image of the scene, such as the side of a furnace, from which the surface temperature can be determined. (a) For a black surface at 60?C, determine the emissive power for the spectral region 9 − 12 μ m (b) Calculate the radiant power (W) received by the thermograph in the same range ( 9 − 12 μ m ) when viewing, in a normal direction, a small black wall area, 200 m m 2 , a t T s = 60 ∘ C .The solid angle ω subtended by the aperture of the thermograph when viewed from the target is 0.001 sr. (c) Determine the radiant power (W) received by the thermograph for the same wall area ( 200 m m 2 , ) and solid angle (0.001 sr) when the wall is a gray, opaque, diffuse material at T s = 60 ∘ C with emissivity 0.7 and the surroundings are black at T s u r = 23 ∘ C .
A thermograph is a device responding to the radiant power from the scene, which reaches its radiation detector within the spectral region 9 − 12 μ m . The thermograph provides an image of the scene, such as the side of a furnace, from which the surface temperature can be determined. (a) For a black surface at 60?C, determine the emissive power for the spectral region 9 − 12 μ m (b) Calculate the radiant power (W) received by the thermograph in the same range ( 9 − 12 μ m ) when viewing, in a normal direction, a small black wall area, 200 m m 2 , a t T s = 60 ∘ C .The solid angle ω subtended by the aperture of the thermograph when viewed from the target is 0.001 sr. (c) Determine the radiant power (W) received by the thermograph for the same wall area ( 200 m m 2 , ) and solid angle (0.001 sr) when the wall is a gray, opaque, diffuse material at T s = 60 ∘ C with emissivity 0.7 and the surroundings are black at T s u r = 23 ∘ C .
Solution Summary: The emissive power for the spectral region 9-12m is 145. The temperature of the black surface is the Stefan-Boltzmann constant.
A thermograph is a device responding to the radiant power from the scene, which reaches its radiation detector within the spectral region
9
−
12
μ
m
. The thermograph provides an image of the scene, such as the side of a furnace, from which the surface temperature can be determined.
(a) For a black surface at 60?C, determine the emissive power for the spectral region
9
−
12
μ
m
(b) Calculate the radiant power (W) received by the thermograph in the same range (
9
−
12
μ
m
) when viewing, in a normal direction, a small black wall area,
200
m
m
2
,
a
t
T
s
=
60
∘
C
.The solid angle
ω
subtended by the aperture of the thermograph when viewed from the target is 0.001 sr.
(c) Determine the radiant power (W) received by the thermograph for the same wall area (
200
m
m
2
,
) and solid angle (0.001 sr) when the wall is a gray, opaque, diffuse material at
T
s
=
60
∘
C
with emissivity 0.7 and the surroundings are black at
T
s
u
r
=
23
∘
C
.
The last portion asks you for "net radiant heat flux to the surface", meaning that positive net radiative heat flux means in and negative net radiative heat flux means out. This is opposite the typical sign convention - be aware of this
A thin, disk-shaped silicon wafer of diameter D=20 cm on a production line must be maintained at a temperature of 100 deg C. The wafer loses heat to the room by convection and radiation from its upper surface, while heat is supplied at a constant flux from below. The surrounding air is at 20 deg C, while all surrounding surfaces (which can be treated as blackbodies) can be approximated to be isothermal at a temperature of 15 deg C. The wafer-to-air heat transfer coefficient is 30 W/m2-K and the emissivity of the wafer’s surface (which can be approximated to be gray) is 0.85. How much heat (in W) must be supplied to the wafer?
Wien's law is stated as follows: AmT = C, where C is 2898 μmK and Am is the wavelength at which the emissive
power of a black body is maximum for a given temperature T. The spectral hemispherical emissivity (Ex) of a surface
is shown in the figure below (1Å= 10-¹0m). The temperature at which the total hemispherical emissivity will be
highest is
K (round off to the nearest integer).
Ext
n
5000
6000 7000 (A)
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