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One scheme for extending the operation of gas turbine blades to higher temperatures involves applying a ceramic coating to the surfaces of blades fabricated from a superalloy such as inconel. To assess the reliability of such coatings, an apparatus has been developed for testing samples under laboratory conditions. The sample is placed at the bottom of a large vacuum chamber whose walls are cryogenically cooled and which is equipped with a radiation detector at the top surface. The detector has a surface area of
Consider conditions for which a ceramic coating of thickness
(a) Consider steady-state conditions for which the bottom surface of the substrate is maintained at
(b) For the prescribed conditions, what is the rate at which radiation emitted by the ceramic is intercepted by the detector?
(c) After repeated experiments, numerous cracks develop at the ceramic−substrate interface, creating an interfacial thermal contact resistance. If
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Fundamentals of Heat and Mass Transfer
- 1.26 Repeat Problem 1.25 but assume that the surface of the storage vessel has an absorbance (equal to the emittance) of 0.1. Then determine the rate of evaporation of the liquid oxygen in kilograms per second and pounds per hour, assuming that convection can be neglected. The heat of vaporization of oxygen at –183°C is .arrow_forwardAn electric heating system is installed in the ceiling of a room 5 m (length) × 5 m (width) ×2.5 m (height). The temperature of the ceiling is 315 K whereas under equilibrium conditions the walls are at 295 K. If the floor is non-sensitive to radiations and the emissivities of the ceiling and wall are 0.75 and 0.65, respectively. Calculate the radiant heat loss from the ceiling to the walls. The answer should be 1595 W. Please show steps in your solutionarrow_forwardProblem (5): Two concentrating collectors (collector A and collector B) have the same concentration factor of CR = 7 and the optical efficiency of nar = 0.88. The collector temperature for both collectors is 145°C and the ambient air temperature is 27°C. The heat transfer coefficient for collector A is 2.5 W/m2.C and that for collector B is 3.5 W/m2.°C. The solar irradiation on collector A is 600 W/m2. (a) At what solar irradiation rate does collector B have the same efficiency as collector A? (b) What is the efficiency change of collector A when the solar irradiation increases to 900 W/m2?arrow_forward
- As far as diathermy concern, we use microwaves to deposit its energy in the surface of fatty layers where as the infrared waves most of it energy is deposited in deep area with fatty layers. O true Falsearrow_forwardHeat lossarrow_forwardAn infrared camera is used to measure a temperature at a tissue location. The infrared camera uses the same equation as that in the lecture notes. When the total hemispherical emissivity is selected as &=1.0, the temperature reading on the camera is 45°C. (a) Based on the equation given in the notes, please calculate the radiation heat flux received by the camera qck. The Stefan-Boltzmann's constant ois 5.67*108 W/(m²K¹). (b) However, you notice that the actual emissivity of the tissue surface should be 0.95. The room temperature is 20°C. Use the equation again to calculate the temperature of the tissue location, note that qck should be the same as in (a). What is the absolute error of the measurement if both the room temperature and deviation from a perfect blackbody surface are not considered?arrow_forward
- 2. A 2-meter section of a 2-cm diameter metal pipe passes through an enclosed furnace. The temperature of the enclosure is at 721 K while the pipe is at 421 K. the emissivity of the metal pipe at 721 K is 0.71 while at 421 K is 0.58. Calculate the heat transfer to the tube by radiation.arrow_forward29. Gamma radiation is bombarding an iron plate as shown in the figure. A con- vection boundary condition of T;= 150 C and h = 200 W/m-K removes heat from the plate. Find the maximum temperature and its location in the plate. Also find temperature at 1 cm from the side facing irradiation and the rate of heat removal from the side not being irradiated. k= 48.5 kW/m K, µ= 24.6 m'. Questions and Problems 507 40 = 19,600 kW/m³ 15 cm T, = 150 C h= 200 W/m K T = 150 C h= 200 W/m Karrow_forwardYou are designing a chamber to contain the radiation emitted by nuclear decay during a fusion reaction. The left face of the (plane) chamber wall (x = 0) is exposed to the radiation and the right face of the wall (x = L) is perfectly insulated. To facilitate the fusion reaction, the left face of the wall is maintained at fixed temperature To. The radiation penetrates the wall causing uniform heat generation that varies with location inside the wall as ) = 40 (1 - 1) g(x) where qo [W/m^3 ] is a constant. Determine an expression for the temperature distribution in the wall T(x) assuming the thermal conductivity of the wall (k) is constant.arrow_forward
- An electric heating system is installed in the ceiling of a room 5 m (length), 5 m (width) and 2.5 m (height). The temperature of the ceiling is 315 K whereas under equilibrium conditions the walls are at 295 K. If the floor is non-sensitive to radiations and the emissivities of the ceiling and wall are 0.75 and 0.65 respectively. Calculate the radiant heat loss from the ceiling to the walls?arrow_forwardGive step-by-step calculation and explanation Consider a person sitting nude on a beach in Florida. On a sunny day, visible radiation energy from the sun is absorbed by the person at a rate of 30 kcal/h or 34.9 W. The air temperature is a warm 30 °C and the individual’s skin temperature is 32 °C. The effective body surface exposed to the sun is 0.9 m². (Assume this same area for sun absorption, radiative transfer, and convective loss. Is this a good assumption?) a. Find the net energy gain or loss from thermal radiation each hour. (Assume thermal radiative gain and loss according to the equation 6.51 in Herman and an emissivity of 1.) -(4). Equalion (6.51) - (40Tin)Eskin Aşkin (Tskin – Troom) dt = (4 x 5.67 x 10¬8 w/m²–K* x (307 K)')€skin Askin (Tskin – Troom). (6.52) b. If there is a 4 m/s breeze, find the energy lost by convection each hour. (Use Eq. 6.61 with eq. 6.63.) 1 Equation he(Tskin – Tair), (6.61) A dt he 10.45 – w + 10w0.5 (6.63) - c. If the individual’s metabolic rate is…arrow_forwardA small sphere (emissivity =0.503 radius=r1) is located at the center of a spherical abestos shell ( thickness =1.74 cm, outer radius= r2; thermal conductivity of abestos is 0.090 J/ (sm c degrees) The thickness of the shell is small compared to the inner and outer radii of the shell. The temperature of the small sphere is 695 degrees Celsius while the temperature of the inner surface of the shell is 352 degrees Celsius, both temperatures remaining constant. Assuming that r2/r1 =8.75 and ignoring any air inside the shell, find the temperature in degrees Celsius of the outer surface of the shell.arrow_forward
- Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning