Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground, T a i r .That is, irradiation from the sky can be expressed as G a t m = ε s k y σ T a i r 4 and for a clear night sky, the emissivity is correlated by an expression of the form ε s k y = 0.741 + 0 .0062T d p , where T d p is the dew point temperature ( c ∘ ) Consider a flat plate exposed to the night sky and in ambient air at 15 ∘ C c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation h ( W / m 2 ⋅ K ) = 1.25 Δ T 1 / 3 , where Δ T is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with ε =0 .23 , and (b) painted with ε =0 .85 ?
Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground, T a i r .That is, irradiation from the sky can be expressed as G a t m = ε s k y σ T a i r 4 and for a clear night sky, the emissivity is correlated by an expression of the form ε s k y = 0.741 + 0 .0062T d p , where T d p is the dew point temperature ( c ∘ ) Consider a flat plate exposed to the night sky and in ambient air at 15 ∘ C c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation h ( W / m 2 ⋅ K ) = 1.25 Δ T 1 / 3 , where Δ T is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with ε =0 .23 , and (b) painted with ε =0 .85 ?
Solution Summary: The author explains the emissivity of the sky, convection coefficient, ambient temperature, relative humidity, and energy balance.
Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground,
T
a
i
r
.That is, irradiation from the sky can be expressed as
G
a
t
m
=
ε
s
k
y
σ
T
a
i
r
4
and for a clear night sky, the emissivity is correlated by an expression of the form
ε
s
k
y
=
0.741
+ 0
.0062T
d
p
,
where T
d
p
is the dew point temperature
(
c
∘
)
Consider a flat plate exposed to the night sky and in ambient air at
15
∘
C
c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation
h
(
W
/
m
2
⋅
K
)
=
1.25
Δ
T
1
/
3
, where
Δ
T
is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with
ε
=0
.23
, and (b) painted with
ε
=0
.85
?
Assume multiple single degree of freedom systems with natural periods T ∈ [0.05, 2.00] seconds with in-crement of period dT = 0.05 seconds. Assume three cases of damping ratio: Case (A) ξ = 0%; Case (B)ξ = 2%; Case (C) ξ = 5%. The systems are initially at rest. Thus, the initial conditions are u(t = 0) = 0 anḋu(t = 0) = 0. The systems are subjected to the base acceleration that was provided in the ElCentro.txt file(i.e., first column). For the systems in Case (A), Case (B), and Case (C) and for each natural period computethe peak acceleration, peak velocity, and peak displacement responses to the given base excitation. Please,use the Newmark method for β = 1/4 (average acceleration) to compute the responses. Create threeplots with three lines in each plot. The first plot will have the peak accelerations in y-axis and the naturalperiod of the system in x-axis. The second plot will have the peak velocities in y-axis and the natural periodof the system in x-axis. The third plot will have…
Both portions of the rod ABC are made of an aluminum for which E = 70 GPa.
Based on the given information find:
1- deformation at A
2- stress in BC
3- Total strain
4- If v (Poisson ratio is 0.25, find the
lateral deformation of AB
Last 3 student ID+ 300 mm=L2
724
A
P=Last 2 student ID+ 300 KN
24
24
Diameter Last 2 student ID+ 15 mm
Last 3 student ID+ 500 mm=L1
724
C
B
24
Q=Last 2 student ID+ 100 KN
24
Diameter Last 2 student ID+ 40 mm
Q2Two wooden members of uniform cross section are joined by the simple scarf splice shown. Knowing that the
maximum allowable tensile stress in the glued splice is 75 psi, determine (a) the largest load P that can be safely
supported, (b) the corresponding shearing stress in the splice.
น
Last 1 student ID+5 inch=W
=9
4
L=Last 1 student ID+8 inch
=12
60°
P'
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