Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground, T a i r .That is, irradiation from the sky can be expressed as G a t m = ε s k y σ T a i r 4 and for a clear night sky, the emissivity is correlated by an expression of the form ε s k y = 0.741 + 0 .0062T d p , where T d p is the dew point temperature ( c ∘ ) Consider a flat plate exposed to the night sky and in ambient air at 15 ∘ C c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation h ( W / m 2 ⋅ K ) = 1.25 Δ T 1 / 3 , where Δ T is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with ε =0 .23 , and (b) painted with ε =0 .85 ?
Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground, T a i r .That is, irradiation from the sky can be expressed as G a t m = ε s k y σ T a i r 4 and for a clear night sky, the emissivity is correlated by an expression of the form ε s k y = 0.741 + 0 .0062T d p , where T d p is the dew point temperature ( c ∘ ) Consider a flat plate exposed to the night sky and in ambient air at 15 ∘ C c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation h ( W / m 2 ⋅ K ) = 1.25 Δ T 1 / 3 , where Δ T is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with ε =0 .23 , and (b) painted with ε =0 .85 ?
Solution Summary: The author explains the emissivity of the sky, convection coefficient, ambient temperature, relative humidity, and energy balance.
Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground,
T
a
i
r
.That is, irradiation from the sky can be expressed as
G
a
t
m
=
ε
s
k
y
σ
T
a
i
r
4
and for a clear night sky, the emissivity is correlated by an expression of the form
ε
s
k
y
=
0.741
+ 0
.0062T
d
p
,
where T
d
p
is the dew point temperature
(
c
∘
)
Consider a flat plate exposed to the night sky and in ambient air at
15
∘
C
c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation
h
(
W
/
m
2
⋅
K
)
=
1.25
Δ
T
1
/
3
, where
Δ
T
is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with
ε
=0
.23
, and (b) painted with
ε
=0
.85
?
The total emissive power of a surface is
500 W/(m ^ 2) at a temperature T1, and
1200 W/(m ^ 2) at a temperature T2 ,where the
temperatures are in Kelvin. Assume the
emissivity of the surface to be constant, find the
ratio of the temperatures T1/T2.
The emissive power of a black body depends on the fourth power of the temperature and is given by W = A T4 Where, W = emissive power, BTUs per square feet per hour A = Stefan Boltzmann constant, 0.171 x 10-8 T = temperature,° Rankine what is the value of A units in J/(m2.
The amount of radiation received per unit time by a person working near a radioactive source, commonly called the dose rate, is measured in rem hr-1. The safety regulations forbid dose rates in excess of 7.5 × 10-4 rem hr-1. The γ dose rate from the 4219K source is found to be 3 × 10-3 rem hr-1 at a distance of 1 m. What is the minimum distance from this source at which itis safe to work? After how long will it be safe to work at a distance of 1 m from the source?
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