Estimate the total, hemispherical emissivity ε for polished stainless steel at 800 K using Equation 12.43 along with information provided in Figure 12.17. Assume that the hemispherical emissivity is equal to the normal emissivity. Perform the integration using a band calculation, by splitting the integral into five bands, each of which contains 20% of the blackbody emission at 800 K. For each band, assume the average emissivity is that associated with the median wavelength within the band λ m , for which half of the blackbody radiation within the band is above λ m (and half is below λ m ). For example, the first band runs from λ = 0 t o λ 1 , such that F ( 0 → λ 1 ) = 0.2 , and the median wavelength for the first band is chosen such that F ( 0 → λ m ) = 0.1 . Also determine the surface emissive power.
Estimate the total, hemispherical emissivity ε for polished stainless steel at 800 K using Equation 12.43 along with information provided in Figure 12.17. Assume that the hemispherical emissivity is equal to the normal emissivity. Perform the integration using a band calculation, by splitting the integral into five bands, each of which contains 20% of the blackbody emission at 800 K. For each band, assume the average emissivity is that associated with the median wavelength within the band λ m , for which half of the blackbody radiation within the band is above λ m (and half is below λ m ). For example, the first band runs from λ = 0 t o λ 1 , such that F ( 0 → λ 1 ) = 0.2 , and the median wavelength for the first band is chosen such that F ( 0 → λ m ) = 0.1 . Also determine the surface emissive power.
Solution Summary: The total emissivity for polished stainless steel is 0.28 and 6502.81 W/m2. The Stefan Boltzmann constant is =5.67108
Estimate the total, hemispherical emissivity
ε
for polished stainless steel at 800 K using Equation 12.43 along with information provided in Figure 12.17. Assume that the hemispherical emissivity is equal to the normal emissivity. Perform the integration using a band calculation, by splitting the integral into five bands, each of which contains 20% of the blackbody emission at 800 K. For each band, assume the average emissivity is that associated with the median wavelength within the band
λ
m
, for which half of the blackbody radiation within the band is above
λ
m
(and half is below
λ
m
). For example, the first band runs from
λ
=
0
t
o
λ
1
, such that
F
(
0
→
λ
1
)
=
0.2
, and the median wavelength for the first band is chosen such that
F
(
0
→
λ
m
)
=
0.1
. Also determine the surface emissive power.
A thin, disk-shaped silicon wafer of diameter D=20 cm on a production line must be maintained at a temperature of 100 deg C. The wafer loses heat to the room by convection and radiation from its upper surface, while heat is supplied at a constant flux from below. The surrounding air is at 20 deg C, while all surrounding surfaces (which can be treated as blackbodies) can be approximated to be isothermal at a temperature of 15 deg C. The wafer-to-air heat transfer coefficient is 30 W/m2-K and the emissivity of the wafer’s surface (which can be approximated to be gray) is 0.85. How much heat (in W) must be supplied to the wafer?
The last portion asks you for "net radiant heat flux to the surface", meaning that positive net radiative heat flux means in and negative net radiative heat flux means out. This is opposite the typical sign convention - be aware of this
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