The spectral distribution of the radiation emitted by a diffuse surface may be approximated as follows. (a) What is the total emissive power? (b) What is the total intensity of the radiation emittedin the normal direction and at an angle of 30 ∘ from the normal? (c) Determine the fraction of the emissive power leaving the surface in the directions π / 4 ≤ θ = π / 2 .use.
The spectral distribution of the radiation emitted by a diffuse surface may be approximated as follows. (a) What is the total emissive power? (b) What is the total intensity of the radiation emittedin the normal direction and at an angle of 30 ∘ from the normal? (c) Determine the fraction of the emissive power leaving the surface in the directions π / 4 ≤ θ = π / 2 .use.
Solution Summary: The spectral distribution of the radiation emitted by diffuse surface is shown below.
The spectral distribution of the radiation emitted by a diffuse surface may be approximated as follows.
(a) What is the total emissive power? (b) What is the total intensity of the radiation emittedin the normal direction and at an angle of
30
∘
from the normal? (c) Determine the fraction of the emissive power leaving the surface in the directions
π
/
4
≤
θ
=
π
/
2
.use.
Determine the following:
a. Average emissivity of both surfaces
b. Absorptivity of both surfaces
c. reflectivity of both surfaces
d. which surface is more suitable to serve as a solar absorber?
The variations of the spectral emissivity of two surfaces are as given:
Surface 1:
ɛ1=0.3 0 ≤ λ < 4 µm
ɛ2=0.8 4 µm ≤ λ < ∞
Surface 2:
ɛ1=0.9 0 ≤ λ < 4 µm
ɛ2=0.2 4 µm ≤ λ < ∞
Draw the spectral emissivities of two surfaces. Determine the average emissivity of each surface at T=4000 K. Also, determine the average absorptivity and reflectivity of each surface for radiation coming from a source at 4000 K. Which surface is more suitable to serve as a solar absorber?
Consider an ideal gas enclosed in a spectral tube. When a high voltage is placed across the tube, many atoms are excited, and all excited atoms emit electromagnetic radiation at characteristic frequencies. According to the Doppler effect, the frequencies observed in the laboratory depend on the velocity of the emitting atom. The nonrelativistic Doppler shift of radiation emitted in the x direction is f = f0(1 + vx / c). The resulting wavelengths observed in the spectroscope are spread to higher and lower values because of the (respectively) lower and higher frequencies, corresponding to negative and positive values of vx. We say that the spectral line has been Doppler broadened. This is what allows us to see the lines easily in the spectroscope, because the Heisenberg uncertainty principle does not cause signifi cant line broadening in atomic transitions. (a) What is the mean frequency of the radiation observed in the spectroscope? (b) To get an idea of how much the spectral line is…
Vector Mechanics for Engineers: Statics, 11th Edition
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