Chapter 12, Problem 12.63AP

a.

Interpretation Introduction

Interpretation:

The dehydrated product from below alcohol compound while reacting with ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ has to be determined.

Dehydration of alcohol:

Alcohol reacts with strong acid ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ to give alkene. In this reaction, water molecule is eliminated from the reactant, which is called to be dehydration reaction. By breaking of bonds between two adjacent atoms, dehydration reaction occurs. One –OH and one H⁺ will be eliminated from the adjacent carbons leading to dehydration, which is called as elimination reaction. In this elimination reaction, multiple bond formation takes place as reactant loses a water molecule from two adjacent carbons.

b.

Interpretation Introduction

Interpretation:

The dehydrated product from below alcohol compound while reacting with ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ has to be determined.

Concept introduction:

Refer to part “a.”.