Chapter 12, Problem 12.55AP

Interpretation Introduction

Interpretation:

The constitutional isomers of molecular formula ${\text{C}}_7{\text{H}}_{\text{16}}\text{O}$ that contain an alcohol group and have seven carbons in the longest chain structure has to be drawn, and also their IUPAC name is given.

Constitutional isomers:

The compounds, that contain same molecular formula but the atom arrangements are different. That means the structure is different but the molecular formula is same is called constitutional isomers.

Nomenclature of alcohol:

First, find the longest carbon chain, which is bonded with the $\text{-OH}$ group. The alcohol has identified and it could be named as –ol, while the naming of the compound by the suffix. If we are numbering the cyclic compound then $\text{-OH}$ group attached carbon as to be considered as a lowest carbon. Other than $\text{-OH}$ group any other substituents are present need to mention their name in prefix, if more than one substituents are there then need to write in alphaphetical order.  For the parent alkane chain naming need to remove the final e and add –ol. If more than one alcohol is present then need to use di, tri, tetra, etc after the parent name but before the –ol.