The parameters of the diff-amp shown in Figure 11.2 are V + = 5 V V − = − 5 V , I Q = 0.4 mA , and R C = 10 k Ω . The output resistance of the constant-current source is R o = 100 k Ω . The transistor parameters are β = 150 V B E ( on ) = 0.7 V , and V A = ∞ . (a) Determine the dc input base currents. (b) Determine the differential signal input currents if a differential-mode input voltage v d = 10 sin ω t mV is applied. (c) If a common-mode input voltage v c m = 3 sin ω t V is applied, determine the common-mode signal input base currents. (Ans. (a) I B 1 = I B 2 = 1.32 μ A , ( b ) I b = 0.256 sin ω t μ A , ( c ) I b = 0.0993 sin ω t μ A ) .
The parameters of the diff-amp shown in Figure 11.2 are V + = 5 V V − = − 5 V , I Q = 0.4 mA , and R C = 10 k Ω . The output resistance of the constant-current source is R o = 100 k Ω . The transistor parameters are β = 150 V B E ( on ) = 0.7 V , and V A = ∞ . (a) Determine the dc input base currents. (b) Determine the differential signal input currents if a differential-mode input voltage v d = 10 sin ω t mV is applied. (c) If a common-mode input voltage v c m = 3 sin ω t V is applied, determine the common-mode signal input base currents. (Ans. (a) I B 1 = I B 2 = 1.32 μ A , ( b ) I b = 0.256 sin ω t μ A , ( c ) I b = 0.0993 sin ω t μ A ) .
Solution Summary: The author explains the dc input base currents for the differential amplifier circuit, and the two transistors are identical.
The parameters of the diff-amp shown in Figure 11.2 are
V
+
=
5
V
V
−
=
−
5
V
,
I
Q
=
0.4
mA
,
and
R
C
=
10
k
Ω
.
The output resistance of the constant-current source is
R
o
=
100
k
Ω
.
The transistor parameters are
β
=
150
V
B
E
(
on
)
=
0.7
V
,
and
V
A
=
∞
.
(a) Determine the dc input base currents. (b) Determine the differential signal input currents if a differential-mode input voltage
v
d
=
10
sin
ω
t
mV
is applied. (c) If a common-mode input voltage
v
c
m
=
3
sin
ω
t
V
is applied, determine the common-mode signal input base currents. (Ans. (a)
I
B
1
=
I
B
2
=
1.32
μ
A
,
(
b
)
I
b
=
0.256
sin
ω
t
μ
A
,
(
c
)
I
b
=
0.0993
sin
ω
t
μ
A
)
.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.