
Concept explainers
Interpretation:
The maximum vapor density possible at 30 degree Celsius must be explained.
Concept introduction:
Vapor density depends on temperature. Saturated vapor density is the maximum amount of vapor air can hold at a particular temperature.

Answer to Problem 3E
1.7 mol/1000 L.
Explanation of Solution
Maximum vapor density possible for air depends on the place and temperature. At higher temperature more water vapor is required to make saturation of air by water vapor.
The water vapor density versus temperature plot is represented as follows:
From the above plot, at 30 oC, the water vapor density is approximately 1.7 mol/1000 L.
Chapter U3 Solutions
Living by Chemistry
Additional Science Textbook Solutions
Campbell Biology: Concepts & Connections (9th Edition)
College Physics: A Strategic Approach (3rd Edition)
Applications and Investigations in Earth Science (9th Edition)
Campbell Biology in Focus (2nd Edition)
Human Anatomy & Physiology (2nd Edition)
Biology: Life on Earth with Physiology (11th Edition)
- Draw the most stable chair conformation of 1-ethyl-1-methylcyclohexane, clearly showing the axial and equatorial substituents. [4] Draw structures corresponding to the following IUPAC name for each of the following compounds; [5] i) 4-Isopropyl-2,4,5-trimethylheptane ii) trans-1-tert-butyl-4-ethylcyclohexane iii) Cyclobutylcycloheptane iv) cis-1,4-di-isopropylcyclohexane (chair conformation) v) 3-Ethyl-5-isobutylnonanearrow_forwardDraw and name molecules that meet the following descriptions; [4] a) An organic molecule containing 2 sp2 hybridised carbon and 1 sp-hybridised carbon atom. b) A cycloalkene, C7H12, with a tetrasubstituted double bond. Also answer question 2 from the imagearrow_forwardH 14. Draw the line angle form of the following molecule make sure you use the proper notation to indicate spatial positioning of atoms. F F H 15. Convert the following condensed form to line angle form: (CH3)3CCH2COCH2CON(CH2CH3)2arrow_forward
- In a reaction between two reactants A and B, the half-life is the same for both only if(A) the stoichiometry A:B is 1:1.(B) the stoichiometry A:B is 1:2 or 2:1.arrow_forwardIn a reaction between two reactants A and B, the half-life is the same for both.(1) Only if the stoichiometry A:B is 1:1.(2) If the initial quantities of A and B are in their stoichiometric ratios.arrow_forwardThere are 48 pairs of students in the following table. Each pair has quantitatively determined the mass of taurine in a 250 mL can of the popular energy drink marketed as “Munster” using High Performance Liquid Chromatography (HPLC). The class results are presented below: QUESTION: Calculate the measurement of uncertainty and provide the data in a spreadsheet table. Mass of Taurine (mg) Mass of Taurine (mg) (Table continued) 152.01 152.23 151.87 151.45 154.11 152.64 152.98 153.24 152.88 151.45 153.49 152.48 150.68 152.33 151.52 153.63 152.48 151.68 153.17 153.40 153.77 153.67 152.34 153.16 152.57 153.02 152.86 151.50 151.23 152.57 152.72 151.54 146.47 152.38 152.44 152.54 152.53 152.54 151.32 152.87 151.24 153.26 152.02 152.90 152.87 151.49 152.46 152.58arrow_forward
- 1. Predict the organic product(s) of the following reactions. Assume excess of reagents unless otherwise noted. a) &l BH3 •THF b) 1) NaOH 2) H3O+ solve d) ala 1) EtMgBr 2) H3O+ e) H2N سكر CuLi NH2 1) SOCI2 2) EtMgBr 3) H3O+ NC H3O+ Δarrow_forwardThere are 48 pairs of students in the following table. Each pair has quantitatively determined the mass of taurine in a 250 mL can of the popular energy drink marketed as “Munster” using High Performance Liquid Chromatography (HPLC). The class results are presented below: QUESTION: Summarise and report these results including an indication of measurement uncertainty. In both calculation samples calculate if an outlier is present, max value, number of samples, mean, standard deviation, g (suspect), g (critical) and t (critical). Mass of Taurine (mg) Mass of Taurine (mg) (Table continued) 152.01 152.23 151.87 151.45 154.11 152.64 152.98 153.24 152.88 151.45 153.49 152.48 150.68 152.33 151.52 153.63 152.48 151.68 153.17 153.40 153.77 153.67 152.34 153.16 152.57 153.02 152.86 151.50 151.23 152.57 152.72 151.54 146.47 152.38 152.44 152.54 152.53 152.54 151.32…arrow_forwardIndicate the rate expressions for reactions that have order 0, 1, and 2.arrow_forward
- PROBLEMS Q1) Label the following salts as either acidic, basic, or neutral a) Fe(NOx) c) AlBr b) NH.CH COO d) HCOON (1/2 mark each) e) Fes f) NaBr Q2) What is the pH of a 0.0750 M solution of sulphuric acid?arrow_forward8. Draw all the resonance forms for each of the fling molecules or ions, and indicate the major contributor in each case, or if they are equivalent (45) (2) -PH2 سمة مدarrow_forwardA J то گای ه +0 Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01 number of moles= 0.400/277.15 = 0.00144 moles 2 x 0.00 144=0.00288 moves arams of acetophenone = 0.00144 X 120.16 = 0.1739 0.1739x2=0.3469 grams of benzaldehyde = 0.00144X106.12=0.1539 0.1539x2 = 0.3069 Starting materials: 0.3469 Ox acetophenone, 0.3069 of benzaldehyde 3arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





