Chapter U3.65, Problem 4E

Interpretation Introduction

Interpretation: The volume of nitrogen gas needs to be determined.

Concept Introduction: The ideal gas equation is represented as follows:

  $PV=nRT$

Here, P is pressure, V is volume, n is number of moles and T is temperature of the gas.

R is Universal gas constant with value $0.082\text{ L atm/K mol}$ .

Answer to Problem 4E

33.6 L.

Explanation of Solution

At STP, the temperature and pressure values are 273.15 K and 1 atm respectively. Also, the given number of moles of nitrogen gas is 1.5 mol.

The ideal gas equation is represented as follows:

  $PV=nRT$

On rearranging,

  $V=\frac{nRT}{P}$

Putting the values to calculate the volume of nitrogen gas as follows:

  $V=\frac{\left(1.5\text{ mol}\right)\left(0.082\text{ L atm/K mol}\right)\left(273.15\text{ K}\right)}{\left(1\text{ atm}\right)}=33.6\text{ L}$

Conclusion

Thus, the volume of nitrogen gas is 33.6 L.