Living by Chemistry
Living by Chemistry
2nd Edition
ISBN: 9781464142314
Author: Angelica M. Stacy
Publisher: W. H. Freeman
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Chapter U3.54, Problem 7E

(a)

Interpretation Introduction

Interpretation : The proportionality constant, k=VT , at the beginning of the dayis to be calculated.

Concept Introduction : According to Charles’s law, if pressure and the number of particles of a gas remain same, then volume is proportional to the Kelvin temperature. V=kT

(a)

Expert Solution
Check Mark

Answer to Problem 7E

The proportionality constant is, k=83.3L/K at the beginning of the day.

Explanation of Solution

As the temperature decreases, the volume of gas also decreases. The volume is directly proportional to the temperature.

Given:

  Initialvolume=V1=25000LInitial temperature=T1=270C

First change the Celsius temperature to Kelvin

So

  T1=270C=27+273=300K

Using the formula

  k=VT

Find the value of k;

  k=VT=25000L300K=83.3L/K

(b)

Interpretation Introduction

Interpretation : The volume of the balloon when the temperature has dropped to 220Chas to be calculated.

Concept Introduction : Volume is directly proportional to temperature. As the temperature decreases, the volume of gas also decreases.

(b)

Expert Solution
Check Mark

Answer to Problem 7E

The volume of the balloon when the temperature has dropped to 220C =21,476L

Explanation of Solution

As the temperature decreases, the volume of gas also decreases because volume is directly proportional to temperature.

Given:

The new temperature T2=220C

First, change the Celsius temperature to Kelvin

  T2=220C=22+273=295K

Let final volume be V2

Now solving for the volume at 295K;

  V2=kT2=72.8L/K×295=21,476L

(c)

Interpretation Introduction

Interpretation : The proportionality constant, k=VT at the end of the day when the temperature is 15 oC has to be calculated.

Concept Introduction : According to Charles’s law, if pressure and the number of particles of a gas remain same, then volume is proportional to the Kelvin temperature.

  V=kT

(c)

Expert Solution
Check Mark

Answer to Problem 7E

The proportionality constant, k=VT , at the end of the day when the temperature is 150Cissame as that at the beginning of the day, i.e., k=83.3L/K .

Explanation of Solution

The temperatureat the end of the day is 150C.

The proportionality constant is a constant value. It remains same at all times of the day. The value of k=VT the same at the beginning of the day and at the end of the day.

So, k=83.3L/K

Chapter U3 Solutions

Living by Chemistry

Ch. U3.50 - Prob. 4ECh. U3.50 - Prob. 5ECh. U3.50 - Prob. 6ECh. U3.50 - Prob. 7ECh. U3.51 - Prob. 1TAICh. U3.51 - Prob. 1ECh. U3.51 - Prob. 2ECh. U3.51 - Prob. 3ECh. U3.51 - Prob. 4ECh. U3.51 - Prob. 5ECh. U3.51 - Prob. 6ECh. U3.51 - Prob. 7ECh. U3.51 - Prob. 8ECh. U3.51 - Prob. 9ECh. U3.52 - Prob. 1TAICh. U3.52 - Prob. 1ECh. U3.52 - Prob. 2ECh. U3.52 - Prob. 3ECh. U3.52 - Prob. 4ECh. U3.52 - Prob. 5ECh. U3.52 - Prob. 6ECh. U3.52 - Prob. 7ECh. U3.52 - Prob. 8ECh. U3.52 - Prob. 9ECh. U3.53 - Prob. 1TAICh. U3.53 - Prob. 1ECh. U3.53 - Prob. 2ECh. U3.53 - Prob. 3ECh. U3.53 - Prob. 4ECh. U3.53 - Prob. 5ECh. U3.53 - Prob. 6ECh. U3.53 - Prob. 7ECh. U3.53 - Prob. 8ECh. U3.53 - Prob. 9ECh. U3.53 - Prob. 10ECh. U3.53 - Prob. 11ECh. U3.53 - Prob. 12ECh. U3.54 - Prob. 1TAICh. U3.54 - Prob. 1ECh. U3.54 - Prob. 2ECh. U3.54 - Prob. 3ECh. U3.54 - Prob. 4ECh. U3.54 - Prob. 5ECh. U3.54 - Prob. 6ECh. U3.54 - Prob. 7ECh. U3.54 - Prob. 8ECh. U3.55 - Prob. 1TAICh. U3.55 - Prob. 1ECh. U3.55 - Prob. 2ECh. U3.55 - Prob. 3ECh. U3.55 - Prob. 4ECh. U3.55 - Prob. 5ECh. U3.55 - Prob. 6ECh. U3.56 - Prob. 1TAICh. U3.56 - Prob. 1ECh. U3.56 - Prob. 2ECh. U3.56 - Prob. 3ECh. U3.56 - Prob. 4ECh. U3.56 - Prob. 5ECh. U3.56 - Prob. 6ECh. U3.56 - Prob. 7ECh. U3.56 - Prob. 8ECh. U3.56 - Prob. 9ECh. U3.56 - Prob. 10ECh. U3.57 - Prob. 1TAICh. U3.57 - Prob. 1ECh. U3.57 - Prob. 2ECh. U3.57 - Prob. 3ECh. U3.57 - Prob. 4ECh. U3.57 - Prob. 5ECh. U3.57 - Prob. 6ECh. U3.57 - Prob. 7ECh. U3.57 - Prob. 8ECh. U3.57 - Prob. 10ECh. U3.58 - Prob. 1TAICh. U3.58 - Prob. 1ECh. U3.58 - Prob. 2ECh. U3.58 - Prob. 4ECh. U3.58 - Prob. 5ECh. U3.58 - Prob. 6ECh. U3.58 - Prob. 7ECh. U3.59 - Prob. 1TAICh. U3.59 - Prob. 1ECh. U3.59 - Prob. 2ECh. U3.59 - Prob. 3ECh. U3.59 - Prob. 4ECh. U3.59 - Prob. 5ECh. U3.60 - Prob. 1TAICh. U3.60 - Prob. 1ECh. U3.60 - Prob. 2ECh. U3.60 - Prob. 3ECh. U3.60 - Prob. 4ECh. U3.60 - Prob. 5ECh. U3.60 - Prob. 6ECh. U3.60 - Prob. 7ECh. U3.60 - Prob. 8ECh. U3.61 - Prob. 1TAICh. U3.61 - Prob. 1ECh. U3.61 - Prob. 2ECh. U3.61 - Prob. 3ECh. U3.61 - Prob. 4ECh. U3.61 - Prob. 5ECh. U3.61 - Prob. 6ECh. U3.61 - Prob. 7ECh. U3.62 - Prob. 1TAICh. U3.62 - Prob. 1ECh. U3.62 - Prob. 2ECh. U3.63 - Prob. 1TAICh. U3.63 - Prob. 1ECh. U3.63 - Prob. 2ECh. U3.63 - Prob. 3ECh. U3.63 - Prob. 4ECh. U3.63 - Prob. 5ECh. U3.63 - Prob. 6ECh. U3.63 - Prob. 7ECh. U3.63 - Prob. 8ECh. U3.64 - Prob. 1TAICh. U3.64 - Prob. 1ECh. U3.64 - Prob. 2ECh. U3.64 - Prob. 3ECh. U3.64 - Prob. 4ECh. U3.64 - Prob. 5ECh. U3.64 - Prob. 6ECh. U3.64 - Prob. 7ECh. U3.65 - Prob. 1TAICh. U3.65 - Prob. 1ECh. U3.65 - Prob. 2ECh. U3.65 - Prob. 3ECh. U3.65 - Prob. 4ECh. U3.65 - Prob. 5ECh. U3.65 - Prob. 6ECh. U3.65 - Prob. 7ECh. U3.65 - Prob. 8ECh. U3.66 - Prob. 1TAICh. U3.66 - Prob. 1ECh. U3.66 - Prob. 2ECh. U3.66 - Prob. 3ECh. U3.66 - Prob. 4ECh. U3.66 - Prob. 5ECh. U3.66 - Prob. 6ECh. U3.66 - Prob. 7ECh. U3.66 - Prob. 8ECh. U3.66 - Prob. 9ECh. U3.66 - Prob. 10ECh. U3.66 - Prob. 11ECh. U3.66 - Prob. 12ECh. U3.67 - Prob. 1TAICh. U3.67 - Prob. 1ECh. U3.67 - Prob. 2ECh. U3.67 - Prob. 4ECh. U3 - Prob. C10.1RECh. U3 - Prob. C10.2RECh. U3 - Prob. C10.3RECh. U3 - Prob. C10.4RECh. U3 - Prob. C10.5RECh. U3 - Prob. C11.1RECh. U3 - Prob. C11.2RECh. U3 - Prob. C11.3RECh. U3 - Prob. C11.4RECh. U3 - Prob. C11.5RECh. U3 - Prob. C12.1RECh. U3 - Prob. C12.2RECh. U3 - Prob. C12.3RECh. U3 - Prob. C12.4RECh. U3 - Prob. C12.5RECh. U3 - Prob. 1RECh. U3 - Prob. 2RECh. U3 - Prob. 3RECh. U3 - Prob. 4RECh. U3 - Prob. 5RECh. U3 - Prob. 6RECh. U3 - Prob. 7RECh. U3 - Prob. 8RECh. U3 - Prob. 9RECh. U3 - Prob. 10RECh. U3 - Prob. 11RECh. U3 - Prob. 12RECh. U3 - Prob. 13RECh. U3 - Prob. 1STPCh. U3 - Prob. 2STPCh. U3 - Prob. 3STPCh. U3 - Prob. 4STPCh. U3 - Prob. 5STPCh. U3 - Prob. 6STPCh. U3 - Prob. 7STPCh. U3 - Prob. 8STPCh. U3 - Prob. 9STPCh. U3 - Prob. 10STPCh. U3 - Prob. 11STPCh. U3 - Prob. 12STPCh. U3 - Prob. 13STPCh. U3 - Prob. 14STPCh. U3 - Prob. 15STPCh. U3 - Prob. 16STPCh. U3 - Prob. 17STPCh. U3 - Prob. 18STPCh. U3 - Prob. 19STPCh. U3 - Prob. 20STP
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