Chapter 9.3, Problem 36PP

Interpretation Introduction

Interpretation:

The chemical, complete ionic and net ionic reaction between aqueous solution of ammonium phosphate and sodium sulfate needs to be represented.

Concept introduction:

The molecular equation of a chemical reaction represents the reactant and product molecules as their molecular formula. The physical states of substances should be written in parenthesis. The ionic equation can be written in which all aqueous substance must be written as their ions.

The net ionic equation is modified form of ionic equation in which the spectator ions must be cancelled from both sides.

Answer to Problem 36PP

No net ionic equation is there for the given reaction.

Explanation of Solution

Given information:

Reaction between aqueous solution of ammonium phosphate and sodium sulfate does not form any precipitate and no gas is evolved.

The molecular reaction equation between aqueous solution of ammonium phosphate and sodium sulfate can be written as:

${\text{2 (NH}}_{\text{4}}{\text{)}}_{\text{3}}{\text{PO}}_{\text{4}}{\text{(aq) + 3 Na}}_{\text{2}}{\text{SO}}_{\text{4}}\text{(aq)}\stackrel{}{\to }{\text{3 (NH}}_{\text{4}}{\text{)}}_{\text{2}}{\text{SO}}_{\text{4}}{\text{(aq) + 2 Na}}_{\text{3}}{\text{PO}}_{\text{4}}\text{(aq)}$

Since all compounds are in aqueous state so ionic equation must be:

${\text{6 NH}}_{{}_{\text{4}}}^{\text{+}}{\text{(aq)+ 2 PO}}_{{}_{\text{4}}}^{\text{-3}}{\text{(aq) + 6 Na}}_{{}_{}}^{\text{+}}{\text{(aq) + 6 SO}}_{{}_{\text{4}}}^{\text{-2}}\text{(aq)}\stackrel{}{\to }{\text{NH}}_{{}_{\text{4}}}^{\text{+}}{\text{(aq)+ 6 SO}}_{{}_{\text{4}}}^{\text{-2}}\text{(aq)}+{\text{6 Na}}_{{}_{}}^{\text{+}}\text{(aq) }+{\text{2 PO}}_{{}_{\text{4}}}^{\text{-3}}\text{(aq) }$

Since all ions are in aqueous state therefore there is no net ionic equation.

Conclusion

Since there is no precipitate and no gas evolved therefore there is no net ionic equation.