Chapter 9, Problem 87A

Interpretation Introduction

(a)

Interpretation:

The chemical equation for the following reaction needs to be determined.

$\text{Magnesium}\text{bromide}\to$

Concept introduction:

A decomposition reaction is one in which a single compound splits into two or more elements or new compounds. In general, decomposition reactions are expressed as follows.

$\text{AB }\to \text{ A }+\text{ B}$

Answer to Problem 87A

The chemical equation is as follows:

${\text{MgBr}}_{\text{2}}\left(\text{s}\right)\to \text{Mg}\left(\text{s}\right){\text{+Br}}_2\left(\text{l}\right)$

Explanation of Solution

Decomposition reaction of ${\text{MgBr}}_{\text{2}}$ produce liquid Br and solid Mg. The reaction is as follows:

${\text{MgBr}}_{\text{2}}\left(\text{s}\right)\to \text{Mg}\left(\text{s}\right){\text{+Br}}_2\left(\text{l}\right)$

The above reaction is a decomposition reaction as the reactant split into two different elements. The number of atoms participating in the reaction that is in both reactant and product side is equal. Therefore, the chemical equation is balanced.

Interpretation Introduction

(b)

Interpretation:

The chemical equation for the following reaction needs to be determined.

$\text{Cobalt}\left(\text{II}\right)\text{oxide}\to$

Concept introduction:

A decomposition reaction is one in which a single compound splits into two or more elements or new compounds. In general, decomposition reactions are expressed as follows.

$\text{AB }\to \text{ A }+\text{ B}$

Answer to Problem 87A

The chemical equation is as follows:

$\text{2CoO}\left(\text{s}\right)\to 2\text{Co}\left(\text{s}\right){\text{+O}}_2\left(\text{g}\right)$

Explanation of Solution

Decomposition of cobalt (II) oxide produces cobalt and oxygen gas. The reaction is as follows:

$\text{2CoO}\left(\text{s}\right)\to 2\text{Co}\left(\text{s}\right){\text{+O}}_2\left(\text{g}\right)$

The above reaction is a decomposition reaction as the reactant split into two different elements. The number of atoms participating in the reaction that is in both reactant and product side is equal. Therefore, the chemical equation is balanced.

Interpretation Introduction

(c)

Interpretation:

The chemical equation for the following reaction needs to be determined.

$\text{Titanium}\left(\text{IV}\right)\text{hydroxide}\to \text{titanium}\left(\text{IV}\right)\text{oxide}\text{+water}$

Concept introduction:

A decomposition reaction is one in which a single compound splits into two or more elements or new compounds. In general, decomposition reactions are expressed as follows.

$\text{AB }\to \text{ A }+\text{ B}$

Answer to Problem 87A

The chemical equation is as follows:

$\text{Ti}{\left(\text{OH}\right)}_{\text{4}}\to {\text{TiO}}_{\text{2}}\left(\text{s}\right){\text{+2H}}_{\text{2}}\text{O}\left(\text{l}\right)$

Explanation of Solution

Decomposition of titanium (IV) hydroxide produces solid ${\text{TiO}}_{\text{2}}$ and water. The reaction is as follows:

$\text{Ti}{\left(\text{OH}\right)}_{\text{4}}\to {\text{TiO}}_{\text{2}}\left(\text{s}\right){\text{+2H}}_{\text{2}}\text{O}\left(\text{l}\right)$

The above reaction is a decomposition reaction as the reactant split into two different elements. The number of atoms participates in the reaction that is in both reactant and product side is equal. Therefore, the chemical equation is balanced.

Interpretation Introduction

(d)

Interpretation:

The chemical equation for the following reaction needs to be determined.

$\text{Barium}\text{carbonate}\to \text{barium}\text{oxide+carbon}\text{dioxide}$

Concept introduction:

A decomposition reaction is one in which a single compound splits into two or more elements or new compounds. In general, decomposition reactions are expressed as follows.

$\text{AB }\to \text{ A }+\text{ B}$

Answer to Problem 87A

The chemical equation is as follows:

${\text{BaCO}}_{\text{3}}\left(\text{s}\right)\to \text{BaO}\left(\text{s}\right){\text{+CO}}_2\left(\text{g}\right)$

Explanation of Solution

Decomposition reaction of barium carbonate produces solid $\text{BaO}$ and ${\text{CO}}_2$. The reaction is as follows:

${\text{BaCO}}_{\text{3}}\left(\text{s}\right)\to \text{BaO}\left(\text{s}\right){\text{+CO}}_2\left(\text{g}\right)$

The above reaction is a decomposition reaction as the reactant split into two different elements. The number of atoms participate in the reaction that is in both reactant and product side is equal. Therefore, the chemical equation is balanced.