Chapter 9, Problem 80A

Interpretation Introduction

(a)

Interpretation:

The element that will replace the other in a reaction among tin and sodium needs to be determined.

Concept introduction:

The reactivity series of metals is as follows:

Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold

Answer to Problem 80A

Sodium will replace tin in a reaction.

Explanation of Solution

The reactivity series of metals is as follows:

Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold

The metal higher on the series is the most active and the metal lower on the series is less active.

Therefore, sodium will replace tin in a reaction.

(b)

Interpretation Introduction

Interpretation:

The element that will replace the other in a reaction among fluorine and iodine needs to be determined.

Concept introduction:

The activity series of halogens is given as follows:

Fluorine > Chlorine > Bromine > iodine

Answer to Problem 80A

Fluorine will replace iodine.

Explanation of Solution

The activity series of halogens is given as follows:

Fluorine > Chlorine > Bromine > iodine

The halogen higher on the series is the most active and the halogen lower on the series is less active.

Therefore, fluorine will replace iodine.

(c)

Interpretation Introduction

Interpretation:

The element that will replace the other in a reaction among lead and silver needs to be determined.

Concept introduction:

The reactivity series of metals is as follows:

Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold

Answer to Problem 80A

Lead will replace Silver

Explanation of Solution

The reactivity series of metals is as follows:

Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold

The metal higher on the series is the most active and the metal lower on the series is less active.

Therefore, Lead will replace Silver.

(d)

Interpretation Introduction

Interpretation:

The element that will replace the other in a reaction among copper and nickel needs to be determined.

Concept introduction:

The reactivity series of metals is as follows:

Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold

Answer to Problem 80A

Nickel will replace Copper.

Explanation of Solution

The reactivity series of metals is as follows:

Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold

The metal higher on the series is the most active and the metal lower on the series is less active.

Therefore, Nickel will replace Copper.