Chapter 9, Problem 109A

Classify each of the reactions represented by the chemical equations in Quesiton 108.

Interpretation Introduction

(a)

Interpretation:

The type of the word reaction given needs to be determined.

$\text{ammonium}\text{phosphate}\left(aq\right)+\text{chromium}\left(\text{III}\right)\text{bromide}\left(aq\right)\to \text{ammonium}\text{bromide}\left(aq\right)+\text{chromium}\left(\text{III}\right)\text{phosphate}\left(s\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula.

Answer to Problem 109A

Given chemical equation illustrated as a double replacement reaction.

Explanation of Solution

The given word equation is as follows:

$\text{ammonium}\text{phosphate}\left(aq\right)+\text{chromium}\left(\text{III}\right)\text{bromide}\left(aq\right)\to \text{ammonium}\text{bromide}\left(aq\right)+\text{chromium}\left(\text{III}\right)\text{phosphate}\left(s\right)$

For this word equation skeleton equation is as follows:

${\left({\text{NH}}_{\text{4}}\right)}_3{\text{PO}}_{\text{4}}\left(aq\right)+{\text{CrBr}}_{\text{3}}\left(aq\right)\to 3{\text{NH}}_{\text{4}}\text{Br}\left(aq\right)+{\text{CrPO}}_4\left(s\right)$

This chemical equation illustrated as a double replacement reaction. Their anions switch by two compounds.

Interpretation Introduction

Interpretation:

The type of the word reaction given needs to be determined.

$\text{chromium}\left(\text{VI}\right)\text{hydroxide}\left(s\right)\to \text{chromium}\left(\text{VI}\right)\text{oxide}\left(s\right)+\text{water}\left(l\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula.

Answer to Problem 109A

Given chemical equation illustrated as a decomposition reaction.

Explanation of Solution

The given word equation is as follows:

$\text{chromium}\left(\text{VI}\right)\text{hydroxide}\left(s\right)\to \text{chromium}\left(\text{VI}\right)\text{oxide}\left(s\right)+\text{water}\left(l\right)$

For this word equation skeleton equation is as follows:

$\text{Cr}{\left(\text{OH}\right)}_6\left(s\right)\to {\text{CrO}}_{\text{3}}\left(s\right)+3{\text{H}}_{\text{2}}\text{O}\left(l\right)$

In above reaction a single reactant gives rise to multiple products. Thus this chemical equation illustrated as a decomposition reaction.