Chapter 9, Problem 100A

Interpretation Introduction

Interpretation:

The complete ionic equation and net ionic equations for given word chemical reaction needs to be determined.

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula.

Answer to Problem 100A

Complete ionic equation is as follows.

${\text{6H}}^{\text{+}}\left(aq\right){\text{+3S}}^{\text{2}-}\left(aq\right)+2{\text{Fe}}^{\text{3+}}\left(aq\right){\text{+6Br}}^{-}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)+6{\text{H}}^{+}\left(aq\right)+6{\text{Br}}^{-}\left(aq\right)$

Net ionic equation for given reaction is as follows:

${\text{3S}}^{\text{2}-}\left(aq\right)+2{\text{Fe}}^{\text{3+}}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)$

Explanation of Solution

For the given word equation, chemical equation is as follows:

${\text{H}}_{\text{2}}\text{S}\left(aq\right)+{\text{FeBr}}_{\text{3}}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)+\text{HBr}\left(aq\right)$

Now balance the above equation is as follows:

${\text{3H}}_{\text{2}}\text{S}\left(aq\right)+2{\text{FeBr}}_{\text{3}}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)+6\text{HBr}\left(aq\right)$

The ionized form of given chemical reactants and products is as follows:

${\text{6H}}^{\text{+}}\left(aq\right){\text{+3S}}^{\text{2}-}\left(aq\right)+2{\text{Fe}}^{\text{3+}}\left(aq\right){\text{+6Br}}^{-}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)+6{\text{H}}^{+}\left(aq\right)+6{\text{Br}}^{-}\left(aq\right)$

Net ionic equation eliminates all ions which are shared by both sides. Thus net ionic equation is as follows:

${\text{3S}}^{\text{2}-}\left(aq\right)+2{\text{Fe}}^{\text{3+}}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)$

Conclusion

Net ionic equation eliminates all ions which are shared by both sides. Net ionic equation for given reaction is as follows:

${\text{3S}}^{\text{2}-}\left(aq\right)+2{\text{Fe}}^{\text{3+}}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)$

Complete ionic equation is as follows:

${\text{3H}}_{\text{2}}\text{S}\left(aq\right)+2{\text{FeBr}}_{\text{3}}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)+6\text{HBr}\left(aq\right)$

${\text{6H}}^{\text{+}}\left(aq\right){\text{+3S}}^{\text{2}-}\left(aq\right)+2{\text{Fe}}^{\text{3+}}\left(aq\right){\text{+6Br}}^{-}\left(aq\right)\to {\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)+6{\text{H}}^{+}\left(aq\right)+6{\text{Br}}^{-}\left(aq\right)$