Chapter 9, Problem 105A

Write the word equation for each of these skeleton equations. ${\text{C}}_{\text{6}}{\text{H}}_{\text{6}}$ is the formula for benzene.

1. ${\text{C}}_{\text{6}}{\text{H}}_{\text{6}}{\text{(l) + O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l)}$

${\text{CO(g) + O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}\text{(g)}$

${\text{Cl}}_{\text{2}}\text{(g) + NaBr}(s)\to {\text{NaCl(s) + Br}}_{\text{2}}(g)$

${\text{CaCO}}_{\text{3}}\text{(s) }\to \text{ CaO}(s)+{\text{CO}}_{\text{2}}\text{(g)}$

Interpretation Introduction

(a)

Interpretation:

The word equation for the given reaction needs to be written.

${\text{C}}_{\text{6}}{\text{H}}_{\text{6}}\left(\text{l}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to {\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 105A

The word equation for the reaction,

${\text{C}}_{\text{6}}{\text{H}}_{\text{6}}\left(\text{l}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to {\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)$ can be written as,

$\text{Benzene}\left(\text{l}\right)\text{+}\text{Oxygen}\left(\text{g}\right)\to \text{Carbon}\text{dioxide}\left(\text{g}\right)\text{+}\text{Water}\left(\text{l}\right)$

Explanation of Solution

The word equation for the reaction,

${\text{C}}_{\text{6}}{\text{H}}_{\text{6}}\left(\text{l}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to {\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)$ can be written as,

$\text{Benzene}\left(\text{l}\right)\text{+}\text{Oxygen}\left(\text{g}\right)\to \text{Carbon}\text{dioxide}\left(\text{g}\right)\text{+}\text{Water}\left(\text{l}\right)$

Benzene burns in oxygen to produce heat, light, carbon dioxide and water.

This reaction is a combustion reaction.

Interpretation Introduction

Interpretation:

The word equation for the reaction needs to be determined.

$\text{CO}\left(\text{g}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to {\text{CO}}_{\text{2}}\left(\text{g}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

In Synthesis reaction, two reactants combine to give one larger product.

$\text{A}\text{+}\text{B}\to \text{AB}$

Answer to Problem 105A

The word equation for the reaction,

$\text{CO}\left(\text{g}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to {\text{CO}}_{\text{2}}\left(\text{g}\right)$ can be written as,

$\text{Carbon}\text{monoxide}\left(g\right)\text{+}\text{Oxygen}\left(\text{g}\right)\to \text{Carbon}\text{dioxide}\left(\text{g}\right)$

Explanation of Solution

The word equation for the reaction,

$\text{CO}\left(\text{g}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to {\text{CO}}_{\text{2}}\left(\text{g}\right)$ can be written as,

$\text{Carbon}\text{monoxide}\left(g\right)\text{+}\text{Oxygen}\left(\text{g}\right)\to \text{Carbon}\text{dioxide}\left(\text{g}\right)$

Carbon monoxide reacts with oxygen to produce carbon dioxide. Therefore, this is a type of synthesis reaction.

Interpretation Introduction

Interpretation:

The word equation for the reaction needs to be determined.

${\text{Cl}}_{\text{2}}\left(\text{g}\right)\text{+}\text{NaBr}\left(\text{s}\right)\to \text{NaCl}\left(\text{s}\right)\text{+}{\text{Br}}_{\text{2}}\left(\text{g}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 105A

The word equation for the reaction,

${\text{Cl}}_{\text{2}}\left(\text{g}\right)\text{+}\text{NaBr}\left(\text{s}\right)\to \text{NaCl}\left(\text{s}\right)\text{+}{\text{Br}}_{\text{2}}\left(\text{g}\right)$ can be written as,

$\text{Chlorine}\left(\text{g}\right)\text{+}\text{Sodiumbromide}\left(\text{s}\right)\to \text{Sodium}\text{chloride}\left(\text{s}\right)+\text{Dibromide}\left(\text{g}\right)$

Explanation of Solution

The word equation for the reaction,

${\text{Cl}}_{\text{2}}\left(\text{g}\right)\text{+}\text{NaBr}\left(\text{s}\right)\to \text{NaCl}\left(\text{s}\right)\text{+}{\text{Br}}_{\text{2}}\left(\text{g}\right)$ can be written as,

$\text{Chlorine}\left(\text{g}\right)\text{+}\text{Sodiumbromide}\left(\text{s}\right)\to \text{Sodium}\text{chloride}\left(\text{s}\right)+\text{Dibromide}\left(\text{g}\right)$

Chlorine reacts with Sodium bromide to give sodium chloride and dibromide. This is an example of single replacement reaction.

Interpretation Introduction

Interpretation:

The word equation for the reaction needs to be determined.

${\text{CaCO}}_{\text{3}}\left(\text{s}\right)\to \text{CaO}\left(\text{s}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 105A

Word equation for the reaction,

${\text{CaCO}}_{\text{3}}\left(\text{s}\right)\to \text{CaO}\left(\text{s}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$ can be written as,

$\text{Calcium}\text{carbonate}\left(\text{s}\right)\to \text{Calcium}\text{oxide}\left(\text{s}\right)\text{+}\text{Carbon}\text{dioxide}\left(\text{g}\right)$

Explanation of Solution

The word equation for the reaction,

${\text{CaCO}}_{\text{3}}\left(\text{s}\right)\to \text{CaO}\left(\text{s}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$ can be written as,

$\text{Calcium}\text{carbonate}\left(\text{s}\right)\to \text{Calcium}\text{oxide}\left(\text{s}\right)\text{+}\text{Carbon}\text{dioxide}\left(\text{g}\right)$

Calcium carbonate decomposes to generate calcium oxide and carbon dioxide. This is an example of decomposition reaction.