Chapter 9.3, Problem 54SSC

Interpretation Introduction

Interpretation:

The given chemical equation needs to be balanced.

${\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+HCl}\left(\text{aq}\right)\to$

Concept introduction:

For balancing an equation first write the skeleton equation. After that count the atoms of both side, count each polyatomic ion as a single element. Find the correct coefficient and placed them in front of the atoms and checked both side element equal or not.

Answer to Problem 54SSC

The complete and balance equation is ${\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+4HCl}\left(\text{aq}\right)\to {\text{CCl}}_{\text{4}}\left(\text{aq}\right){\text{+2H}}_{\text{2}}\text{O}\left(\text{l}\right)$.

Explanation of Solution

Now, write the skeleton equations for ${\text{CO}}_{\text{2}}$ and $\text{HCl}$ as follows:

${\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+HCl}\left(\text{aq}\right)\to {\text{CCl}}_{\text{4}}\left(\text{aq}\right){\text{+H}}_{\text{2}}\text{O}\left(\text{l}\right)$

In reactant side number of C is 1, O is 2, H is 1 and Cl atom is 1 while in product side number of C is 1, Cl is 4, H is 2 and oxygen is 1. To balance H and Cl in both sides give coefficient 4 to $\text{HCl}$ and product 2 to ${\text{H}}_{\text{2}}\text{O}$. Therefore, the balance equation is as follows:

${\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+4HCl}\left(\text{aq}\right)\to {\text{CCl}}_{\text{4}}\left(\text{aq}\right){\text{+2H}}_{\text{2}}\text{O}\left(\text{l}\right)$

Conclusion

The complete and balance equation is ${\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+4HCl}\left(\text{aq}\right)\to {\text{CCl}}_{\text{4}}\left(\text{aq}\right){\text{+2H}}_{\text{2}}\text{O}\left(\text{l}\right)$.