Chapter 9, Problem 85A

Interpretation Introduction

(a)

Interpretation:

The chemical equation for the reaction needs to be written.

$\text{boron}\text{+}\text{fluorine}\to$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 85A

Chemical equation for the reaction is,

$\text{2B}\text{+}{\text{3F}}_{\text{2}}\to {\text{2BF}}_{\text{3}}$

Explanation of Solution

Chemical equation for the reaction,

$\text{boron}\text{+}\text{fluorine}\to$ is,

$\text{2B}\text{+}{\text{3F}}_{\text{2}}\to {\text{2BF}}_{\text{3}}$

Boron reacts with fluorine to give boron trifluoride.

(b)

Interpretation Introduction

Interpretation:

The chemical equation for the reaction needs to be determined.

$\text{germanium}\text{+}\text{sulfur}\to$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 85A

Chemical equation for the reaction is,

$\text{Ge}\text{+}\text{2S}\stackrel{60{\text{0}}^{\text{0}}\text{C}-{\text{800}}^{\text{0}}\text{C}}{\to }{\text{GeS}}_{\text{2}}$

Explanation of Solution

The chemical equation for the reaction,

$\text{germanium}\text{+}\text{sulfur}\to$ is,

$\text{Ge}\text{+}\text{2S}\stackrel{60{\text{0}}^{\text{0}}\text{C}-{\text{800}}^{\text{0}}\text{C}}{\to }{\text{GeS}}_{\text{2}}$

Germanium reacts with Sulphur at a temperature of 6000 C – 8000 C to give ${\text{GeS}}_{\text{2}}$

(c)

Interpretation Introduction

Interpretation:

The chemical equation for the reaction needs to be determined.

$\text{Zirconium}\text{+}\text{nitrogen}\to$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 85A

The chemical equation for the reaction is,

$\text{2Zr}\text{+}{\text{N}}_{\text{2}}\stackrel{{700}^0-{800}^0\text{C}}{\to }\text{2ZrN}$

Explanation of Solution

Chemical equation for the reaction,

$\text{Zirconium}\text{+}\text{nitrogen}\to$ is

$\text{2Zr}\text{+}{\text{N}}_{\text{2}}\stackrel{{700}^0-{800}^0\text{C}}{\to }\text{2ZrN}$

Zr reacts with Nitrogen at a temperature of 7000 C – 8000C to give $\text{2ZrN}$

(d)

Interpretation Introduction

Interpretation:

The chemical equation for the reaction needs to be determined.

$\text{tetraphosphorus}\text{decoxide}\text{+}\text{water}\to$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 85A

Chemical equation for the reaction is,

${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}\left(\text{aq}\right)\text{+}{\text{6H}}_{\text{2}}\text{O}\left(\text{l}\right)\to {\text{4H}}_{\text{3}}{\text{PO}}_{\text{4}}\left(\text{aq}\right)$

Explanation of Solution

Chemical equation for the reaction,

$\text{tetraphosphorus}\text{decoxide}\text{+}\text{water}\to$

${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}\left(\text{aq}\right)\text{+}{\text{6H}}_{\text{2}}\text{O}\left(\text{l}\right)\to {\text{4H}}_{\text{3}}{\text{PO}}_{\text{4}}\left(\text{aq}\right)$

${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}$ reacts with water to generate ${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}$